# Calculate the standard enthalpy change for the fermentation process, in which glucose (C6H12O6) is converted into ethanol (C2H5OH) and carbon dioxide (CO2). Substance Enthalpy of Formation,ΔHo fCO2 (g) −393.5 kJ/molCO2 (aq) −412.9 kJ/molC2H5OH (l) −276.98 kJ/molC6H12O6 (s) −1,274.5 kJ/molH2O (g) −241.8 kJ/molH2O (l) −285.8 kJ/molO2 (g) 0 kJ/mol

Question
26 views

Calculate the standard enthalpy change for the fermentation process, in which glucose (C6H12O6) is converted into ethanol (C2H5OH) and carbon dioxide (CO2).

Substance

Enthalpy of Formation,
Δ
H
 o f
CO2 (g)   −393.5 kJ/mol
CO2 (aq)   −412.9 kJ/mol
C2H5OH (l)   −276.98 kJ/mol
C6H12O6 (s)   −1,274.5 kJ/mol
H2O (g)   −241.8 kJ/mol
H2O (l)   −285.8 kJ/mol
O2 (g)   0 kJ/mol
check_circle

Step 1

Thermodynamic is the branch of chemistry that mainly deals with the heat transfer between system and surroundings. Here system is the substance for which the heat content is studied and remaining part of universe is consider as the surroundings.

Step 2

The heat content of any substance can be expressed in terms of heat capacity or specific heat. Heat capacity can be defined as the amount of heat to be supplied to a given mass of substance to produce a unit change in its temperature.

The enthalpy of formation of reactant and product can be used to calculate the enthalpy change for the given reaction.

The given reaction of fermentation of glucose to ethanol and carbon dioxide gas is: help_outlineImage Transcriptionclose-2 CH,OΗ+2CO9 +2x ΔΗ, 1 -ΔcΗ,Ο ι ) CH120 ΔΗ-2x ΔΗ.,.Οι +2 x ΔΗ, 1-ΔΗ '6(s) fullscreen
Step 3

Substitute the given values of enthalpy of form... help_outlineImage TranscriptioncloseДН - [2х ДН,нон +2х ДН о, 1 -АН, CH1206) AH [2 x -276.98KJ/mol +2 x -393.5 kJ/mol ] - [-1274.5 kJ/mol] AH [-553.96 kJ/mol -787 kJ/mol ] +1274.5 kJ/mol AH66.46 kJ/mol fullscreen

### Want to see the full answer?

See Solution

#### Want to see this answer and more?

Solutions are written by subject experts who are available 24/7. Questions are typically answered within 1 hour.*

See Solution
*Response times may vary by subject and question.
Tagged in

### Other 