Calculate the standard enthalpy for the reaction: 4NH3(g) + 502(g) - 4NO(g) + 6H2O(g), given the following data: N2(g) + O2(g) → 2NO(g) AHrxn = 1 -43.1 kcal mol N2(g) + 3H2(g) → 2NH3(g) AHrxn = -21.9 kcal mol1 2H2(g) + O2(g) – 2H20(g) AHrxn = -115.6 kcal mol1 Round your answer to 2 decimal places.

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