Question
Asked Sep 29, 2019
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Calculate the standard error. May normality be assumed? (Round your answers to 4 decimal places.)
 

    Standard Error   Normality
(a) n = 27, ππ = .35       (Click to select)   Yes   No 
(b) n = 48, ππ = .53       (Click to select)   Yes   No 
(c) n = 110, ππ = .41       (Click to select)   Yes   No 
(d) n = 489, ππ = .006       (Click to select)   Yes   No 
 
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Expert Answer

Step 1

(a)

 

The standard error is 0.0918 and it is calculated below:

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т (1-т) Standard Error п 0.35(1-0.35) 27 =0.0918

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Step 2

The conditions for normality are, np>=10 and n(1-p)>=10.

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np 27x0.35 = 9.45 <10

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Step 3

The normality condition is not satisfied.

No. The normality is not assumed.

 

(b)

 

The standard er...

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(т (1-т) Standard Error п 0.53 (1 -0.53) 48 = 0.0720 np = 48 x0.53 25.44 >10 п(1- р) — 48х0.47 = 22.56 >10

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