Calculate the value of ml for a proton constrained to rotate in a circle of radius 100 pm around a fixed point given that the rotational energy is equal to the classical average energy at 25 degrees C. (Mass of a proton = 1.6726 x 10^-27 kg, classical average energy=1/2kBT, where kBT is Boltzman constant = 1.30 x 10^ -23 J K^-1, and T is the temperature.)

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Asked Sep 26, 2019
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Calculate the value of ml for a proton constrained to rotate in a circle of radius 100 pm around a fixed point given that the rotational energy is equal to the classical average energy at 25 degrees C. 

(Mass of a proton = 1.6726 x 10^-27 kg, classical average energy=1/2kBT, where kBT is Boltzman constant = 1.30 x 10^ -23 J K^-1, and T is the temperature.) 

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Step 1

It is given that:

Radius = 100 pm

Temperature = 25 ͦC

Mass of proton = 1.6726×10-27 kg

Step 2

For a particle in a ring the energy level is given as follows:

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E 21 m 2mr where, m is mass of proton is the radius his having value 1.0546 1034 J.s

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Step 3

Also, the expression for classi...

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E= T where, k, is boltzman constant T is the temperature

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