Question
Asked Dec 18, 2019
12 views

Capacitors C1 = 6.0 µF and C2 = 2.0 µF are charged as a parallel
combination across a 250 - V battery. The capacitors are
disconnected from the battery and from each other. They are
then connected positive plate to negative plate and negative
plate to positive plate. Calculate the resulting charge on each
capacitor.

check_circle

Expert Answer

Step 1

Given:

C1 = 6 μF

C2 = 2 μF

Applied voltage = 250 V

Given:

C1 = 6 μF

C2 = 2 μF

Applied voltage = 250 V

Given:

C1 = 6 μF

C2 = 2 μF

Applied voltage = 250 V

Given:

C1 = 6 μF

C2 = 2 μF

Applied voltage = 250 V

help_outline

Image Transcriptionclose

Given: C; = 6 µF C2 = 2 µF Applied voltage = 250 V

fullscreen
Step 2
help_outline

Image Transcriptionclose

Equivalent capacitance for parallel combination can be calculated as Cag = G +C, C, =6+2 C = 8µF %3D

fullscreen
Step 3
help_outline

Image Transcriptionclose

In parallel combination voltage across each capacitor is same. Therefore, V = V, =V = 250 V

fullscreen

Want to see the full answer?

See Solution

Check out a sample Q&A here.

Want to see this answer and more?

Solutions are written by subject experts who are available 24/7. Questions are typically answered within 1 hour.*

See Solution
*Response times may vary by subject and question.
Tagged in
SciencePhysics

Electrostatic Potential and Capacitance

Related Physics Q&A

Find answers to questions asked by student like you
Show more Q&A
add