Carbon occurs in two forms, graphite and diamond. The enthalpy of the combustion of graphite is -393.5 kJ/mol and that of diamond is -395.4 kJ/mol: C (graphite) + O2 (g) C (diamond) + O2 (g) → CO2 (g) AH1 = -393.5 kJ CO2 (g) AH2 = -395.4 kJ Calculate AH3 for the conversion of graphite to diamond: C (graphite) C (diamond) AH3 = ? kJ

Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter5: Thermochemistry
Section: Chapter Questions
Problem 5.99QE
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Carbon occurs in two forms, graphite and diamond. The
enthalpy of the combustion of graphite is -393.5 kJ/mol
and that of diamond is -395.4 kJ/mol:
C (graphite) + O2 (g) → CO2 (g)
C (diamond) + 02 (g)
AH1 = -393.5 kJ
CO2 (g)
AH2 = -395.4 kJ
Calculate AH3 for the conversion of graphite to diamond:
C (graphite)
C (diamond)
AH3 = ? kJ
%3D
Transcribed Image Text:Carbon occurs in two forms, graphite and diamond. The enthalpy of the combustion of graphite is -393.5 kJ/mol and that of diamond is -395.4 kJ/mol: C (graphite) + O2 (g) → CO2 (g) C (diamond) + 02 (g) AH1 = -393.5 kJ CO2 (g) AH2 = -395.4 kJ Calculate AH3 for the conversion of graphite to diamond: C (graphite) C (diamond) AH3 = ? kJ %3D
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