Carbonyl bromide can dissociate into carbon monoxide and bromine: ? COBR2(9) CO(g) + Br₂(g) At 73 °C, the equilibrium constant in terms of pressures, Kp, for this dissociation reaction is 5.40. (a) If 15.67 g of carbonyl bromide is placed in a 15.56-L vessel and heated to 73 °C, what is the partial pressure of carbon monoxide when equilibrium is attained? (b) What fraction of carbonyl bromide is dissociated at equilibrium? atm

Chemistry & Chemical Reactivity
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Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
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Chapter15: Principles Of Chemical Reactivity: Equilibria
Section: Chapter Questions
Problem 3PS: Kc = 5.6 1012 at 500 K for the dissociation of iodine molecules to iodine atoms. I2(g) 2 I(g) A...
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Carbonyl bromide can dissociate into carbon monoxide and bromine:
?
COBR2(9) CO(g) + Br₂(g)
At 73 °C, the equilibrium constant in terms of pressures, Kp, for this dissociation reaction is 5.40.
(a) If 15.67 g of carbonyl bromide is placed in a 15.56-L vessel and heated to 73 °C, what is the partial pressure of carbon monoxide when equilibrium is attained?
(b) What fraction of carbonyl bromide is dissociated at equilibrium?
atm
Transcribed Image Text:Carbonyl bromide can dissociate into carbon monoxide and bromine: ? COBR2(9) CO(g) + Br₂(g) At 73 °C, the equilibrium constant in terms of pressures, Kp, for this dissociation reaction is 5.40. (a) If 15.67 g of carbonyl bromide is placed in a 15.56-L vessel and heated to 73 °C, what is the partial pressure of carbon monoxide when equilibrium is attained? (b) What fraction of carbonyl bromide is dissociated at equilibrium? atm
The equilibrium constant in terms of pressures for the reaction
CoH5CH2OH(g) ≥ CsH5CHO(s) + Hz(9)
is Kp = 0.558 at 523 K.
(a) A pure sample of gaseous benzyl alcohol, C6H5CH₂OH(g), is introduced into a rigid flask at a temperature of 523 K so that its original pressure is 0.106 atm. Calculate the fraction of this starting material that is converted to products at equilibrium.
(b) A second sample of benzyl alcohol introduced into a rigid flask at a temperature of 523 K, this time at an original pressure of 4.52 atm. Again, calculate the fraction of the starting material that is converted
products at equilibrium.
Transcribed Image Text:The equilibrium constant in terms of pressures for the reaction CoH5CH2OH(g) ≥ CsH5CHO(s) + Hz(9) is Kp = 0.558 at 523 K. (a) A pure sample of gaseous benzyl alcohol, C6H5CH₂OH(g), is introduced into a rigid flask at a temperature of 523 K so that its original pressure is 0.106 atm. Calculate the fraction of this starting material that is converted to products at equilibrium. (b) A second sample of benzyl alcohol introduced into a rigid flask at a temperature of 523 K, this time at an original pressure of 4.52 atm. Again, calculate the fraction of the starting material that is converted products at equilibrium.
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