Chapter 15, Problem 049 The angle (with respect to the vertical) of a simple pendulum is given by e = emcos[(4.96 rad/s)t ]. If at t 0.0350 rad and de/dt = -0.240 rad/s, what are (a) the phase constant o and (b) the maximum angle 8m? (Hint: Don't confuse 0, e the rate d0/dt at which 8 changes with the w of the SHM.) Pivot point 1е\ -Fcose sine (a) (b) (a) Number Unit (b) Number Unit

Physics for Scientists and Engineers: Foundations and Connections
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Author:Katz, Debora M.
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Chapter16: Oscillations
Section: Chapter Questions
Problem 34PQ: Show that angular frequency of a physical pendulum phy=mgrCM/I (Eq. 16.33) equals the angular...
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Chapter 15, Problem 049
The angle (with respect to the vertical) of a simple pendulum is given by e = emcos[(4.96 rad/s)t ]. If at t
0.0350 rad and de/dt = -0.240 rad/s, what are (a) the phase constant o and (b) the maximum angle 8m? (Hint: Don't confuse
0, e
the rate d0/dt at which 8 changes with the w of the SHM.)
Pivot
point
1е\
-Fcose
sine
(a)
(b)
(a) Number
Unit
(b) Number
Unit
Transcribed Image Text:Chapter 15, Problem 049 The angle (with respect to the vertical) of a simple pendulum is given by e = emcos[(4.96 rad/s)t ]. If at t 0.0350 rad and de/dt = -0.240 rad/s, what are (a) the phase constant o and (b) the maximum angle 8m? (Hint: Don't confuse 0, e the rate d0/dt at which 8 changes with the w of the SHM.) Pivot point 1е\ -Fcose sine (a) (b) (a) Number Unit (b) Number Unit
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