= charge 9 placed at center of the hase of a conicat shaped sar face Esme the tatiwing will be the electric flux through the conical surface in SI siest estion to enlarge)
= charge 9 placed at center of the hase of a conicat shaped sar face Esme the tatiwing will be the electric flux through the conical surface in SI siest estion to enlarge)
Chapter6: Gauss's Law
Section: Chapter Questions
Problem 22P: Find the electric flux through a rectangular area 3 cm x 2 cm between parallel plates where there is...
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Handwritten solution required, please do rough and shortcut solution ( do not need of full explanation) and highlight the correct answer as soon as possible.
Transcribed Image Text:Question 13:
Consider a point charge 4 placed at
g/4 = K. what will be the electric flux through the conical surface in si smitsr
center of the hase of a conical shaped sar face the atiing 1iers. 1e det is
(Note:click on Question to entarge)
O K/2
O rhk
O K
O 2K
r
q
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