50 50 50 45 45三 45 40 40= 40 35 35 35 30 30 30 25 255 25 20 20= 20 15 15 15 10 10E 10 5. 0.80 M HCI 1.2 M NaOH 0.60 M HI

Chemistry by OpenStax (2015-05-04)
1st Edition
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter3: Composition Of Substances And Solutions
Section: Chapter Questions
Problem 70E: What mass of a 4.00% NaOH solution by mass contains 15.0 g of NaOH?
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  1. A student combines the solutions below: Calculate the [H3O+] and [OH−] in the resulting solution.
50
50
50
45
45三
45
40
40=
40
35
35
35
30
30
30
25
255
25
20
20=
20
15
15
15
10
10E
10
5.
0.80 M HCI
1.2 M NaOH
0.60 M HI
Transcribed Image Text:50 50 50 45 45三 45 40 40= 40 35 35 35 30 30 30 25 255 25 20 20= 20 15 15 15 10 10E 10 5. 0.80 M HCI 1.2 M NaOH 0.60 M HI
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