Chlorine gas can be prepared in the laboratory by the reaction of hydrochloric acid with manganese(IV) oxide.→ MnCl, (aq) + 2 H,0(1) + CL,(g)4 HC1(aq) + Mn0,(s)—A sample of 37.5 g MnO, is added to a solution containing 43.3 g HCI.What is the limiting reactant?HCIO MnO,What is the theoretical yield of Cl,?theoretical yield:g Cl,If the yield of the reaction is 77.3%, what is the actual yield of chlorine?actual yield:g Cl,

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Asked Dec 5, 2019
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Chlorine gas can be prepared in the laboratory by the reaction of hydrochloric acid with manganese(IV) oxide.
→ MnCl, (aq) + 2 H,0(1) + CL,(g)
4 HC1(aq) + Mn0,(s)
—
A sample of 37.5 g MnO, is added to a solution containing 43.3 g HCI.
What is the limiting reactant?
HCI
O MnO,
What is the theoretical yield of Cl,?
theoretical yield:
g Cl,
If the yield of the reaction is 77.3%, what is the actual yield of chlorine?
actual yield:
g Cl,
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Chlorine gas can be prepared in the laboratory by the reaction of hydrochloric acid with manganese(IV) oxide. → MnCl, (aq) + 2 H,0(1) + CL,(g) 4 HC1(aq) + Mn0,(s) — A sample of 37.5 g MnO, is added to a solution containing 43.3 g HCI. What is the limiting reactant? HCI O MnO, What is the theoretical yield of Cl,? theoretical yield: g Cl, If the yield of the reaction is 77.3%, what is the actual yield of chlorine? actual yield: g Cl,

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Expert Answer

Step 1

Given information:

Mass of MnO2 = 37.5 g

Mass of HCl = 43.3 g

Step 2

The chemical equation for the liberation of chlorine gas is represented as follows:

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4НС (аq) + MnO, (s) -> MnCl, (aq) +2H,0 +C1, (8)

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Step 3

First number of moles of HCl and MnO2 a...

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43.3 g Number of moles of HC1= 36.46094 g/mol nci = 1.1876 mol 37.5 g Number of moles of MnO, 86.9368 g/mol nMmo, = 0.4313 mol

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