Choose the correct answer (Electric potential) - The electric potential at x =3 m is 120 V, and the electric potential at x=5m is 190 V,assuming the field is uniform. The x component of the electric field in this region is: a) -35 N/Cb) 35 N/Cc) 140 N/Cd) -140 N/C 2- The electric potential at y =5 m is 100 V, and the electric potential at y=10 m is 170 V,assuming the field is uniform. The y component of the electric field in this region is:a) -14 N/Cb) 14 N/Cc) -28 N/Cd) 28 N/C 3- An electron in the beam of a typical dental x-ray machine has a kinetic energy 1.07* 10-14 J,this energy is equivalent to: (e = 1.6*10-19 C)a) 1.07* 10-14 eVb) 1.07* 1014 eVc) 6.69*10-4 eVd) 6.69*104 eV 4- An electron in an x-ray machine is accelerated through a potential difference of 5*104 V before it hits the target. The change in electric potential energy is: (e = 1.6*10-19 C)a) -8*10-15 Jb) 8*10-15 Jc) 5*10-13Jd) 9*10-12J 5- A proton is released from rest at the origin in a uniform electric field in the positive x direction with magnitude 3000 N/C. The change in the electric potential energy of the proton–field system when the proton travels to x =5 m is: (e = 1.6*10-19 C)a) 24*10-16Jb) -24*10-16 Jc) 5000 Jd) 1000 J 6- Oppositely charged parallel plates are separated by 5 mm. A potential difference of 600 V exists between the plates. The magnitude of the electric field between the plates is:a) 1.2*105 N/Cb) 1.2*10-5 N/Cc) 2.1*105 N/Cd) 0.12*105 N/C 7- Oppositely charged parallel plates are separated by 4 mm. A potential difference of 500 V exists between the plates. The magnitude of the electric field between the plates is:a) 1.25*105N/Cb) 1.2*10-5N/Cc) 2.1*105 N/Cd) 0.12*105 N/C 8- Oppositely charged parallel plates are separated by 5 mm. The magnitude of the electric field between the plates is 1.2*105 N/C. The work done on the electron to move it to the negative plate is: (assume that it is initially positioned 2 mm from the negative plate),(e=1.6*10-19 C)a) 2.84*10-17 Jb) 4.83*10-17Jc) 1.87*10-17 Jd) 3.84*10-17 J 9- Oppositely charged parallel plates are separated by 4 mm. The magnitude of the electric field between the plates is 1.25105N/C. The work done on the electron to move it to the negative plate is: (assume that it is initially positioned 1.5 mm from the negative plate), (e=1.6*10-19 C)a) 3*10-17 Jb) 4*10-17Jc) 2*10-17 Jd) 7*10-17 J 10- Oppositely charged parallel plates are separated by 0.6 cm. A potential difference of 300 V exists between the plates. The magnitude of the force on an electron between the plates is: (e =1.6*10-19 C)a) 8*10-15 Nb) 0.8 *1014 Nc) 8*1014 Nd)18*10-14 N

Question

Choose the correct answer (Electric potential)

- The electric potential at x =3 m is 120 V, and the electric potential at x=5m is 190 V,assuming the field is uniform. The x component of the electric field in this region is:
a) -35 N/C
b) 35 N/C
c) 140 N/C
d) -140 N/C


2- The electric potential at y =5 m is 100 V, and the electric potential at y=10 m is 170 V,assuming the field is uniform. The y component of the electric field in this region is:
a) -14 N/C
b) 14 N/C
c) -28 N/C
d) 28 N/C


3- An electron in the beam of a typical dental x-ray machine has a kinetic energy 1.07* 10-14 J,this energy is equivalent to: (e = 1.6*10-19 C)
a) 1.07* 10-14 eV
b) 1.07* 1014 eV
c) 6.69*10-4 eV
d) 6.69*104 eV


4- An electron in an x-ray machine is accelerated through a potential difference of 5*104 V before it hits the target. The change in electric potential energy is: (e = 1.6*10-19 C)
a) -8*10-15 J
b) 8*10-15 J
c) 5*10-13J
d) 9*10-12J


5- A proton is released from rest at the origin in a uniform electric field in the positive x direction with magnitude 3000 N/C. The change in the electric potential energy of the proton–field system when the proton travels to x =5 m is: (e = 1.6*10-19 C)
a) 24*10-16J
b) -24*10-16 J
c) 5000 J
d) 1000 J

6- Oppositely charged parallel plates are separated by 5 mm. A potential difference of 600 V exists between the plates. The magnitude of the electric field between the plates is:
a) 1.2*105 N/C
b) 1.2*10-5 N/C
c) 2.1*105 N/C
d) 0.12*105 N/C


7- Oppositely charged parallel plates are separated by 4 mm. A potential difference of 500 V exists between the plates. The magnitude of the electric field between the plates is:
a) 1.25*105N/C
b) 1.2*10-5N/C
c) 2.1*105 N/C
d) 0.12*105 N/C


8- Oppositely charged parallel plates are separated by 5 mm. The magnitude of the electric field between the plates is 1.2*105 N/C. The work done on the electron to move it to the negative plate is: (assume that it is initially positioned 2 mm from the negative plate),(e=1.6*10-19 C)
a) 2.84*10-17 J
b) 4.83*10-17J
c) 1.87*10-17 J
d) 3.84*10-17 J


9- Oppositely charged parallel plates are separated by 4 mm. The magnitude of the electric field between the plates is 1.25105
N/C. The work done on the electron to move it to the negative plate is: (assume that it is initially positioned 1.5 mm from the negative plate), (e=1.6*10-19 C)
a) 3*10-17 J
b) 4*10-17J
c) 2*10-17 J
d) 7*10-17 J


10- Oppositely charged parallel plates are separated by 0.6 cm. A potential difference of 300 V exists between the plates. The magnitude of the force on an electron between the plates is: (e =1.6*10-19 C)
a) 8*10-15 N
b) 0.8 *1014 N
c) 8*1014 N
d)18*10-14 N

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