Circle the solution in each pair with the Higher pH. Lactic acid Ka = 1.4 x 10-4 Hydrocyanic acid Ka= 6.2 x 10-10 a) 0.1 mol L-' hydrobromic acid or 0.2 mol L-' hydrobromic acid b) 0.1 mol L-1 sulfuric acid 0.1 mol L-' hydrobromic acid or c) 0.1 mol L-1 lactic acid 0.1 mol L-' hydrobromic acid or d) 0.1 mol L-l hydrocyanic acid 0.1 mol L-' lactic acid or e) 0.1 mol L-1 lactic acid or 0.1 mol L-1 sodium lactate

Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter16: Reactions Between Acids And Bases
Section: Chapter Questions
Problem 16.80QE: Calculate the pH of each of the following solutions. (a) 10.0 mL of 0.300 M hydrofluoric acid plus...
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Circle the solution in each pair with the Higher pH.
Lactic acid Ka = 1.4 x 10-4
Hydrocyanic acid Ka= 6.2 x 10-10
a) 0.1 mol L-' hydrobromic acid
or
0.2 mol L-' hydrobromic acid
b) 0.1 mol L-1 sulfuric acid
0.1 mol L-' hydrobromic acid
or
c) 0.1 mol L-1 lactic acid
0.1 mol L-' hydrobromic acid
or
d) 0.1 mol L-l hydrocyanic acid
0.1 mol L-' lactic acid
or
e) 0.1 mol L-1 lactic acid
or
0.1 mol L-1 sodium lactate
Transcribed Image Text:Circle the solution in each pair with the Higher pH. Lactic acid Ka = 1.4 x 10-4 Hydrocyanic acid Ka= 6.2 x 10-10 a) 0.1 mol L-' hydrobromic acid or 0.2 mol L-' hydrobromic acid b) 0.1 mol L-1 sulfuric acid 0.1 mol L-' hydrobromic acid or c) 0.1 mol L-1 lactic acid 0.1 mol L-' hydrobromic acid or d) 0.1 mol L-l hydrocyanic acid 0.1 mol L-' lactic acid or e) 0.1 mol L-1 lactic acid or 0.1 mol L-1 sodium lactate
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