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Civil Engineering Question

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Step 1

Consider a small differential element as,

у
х
dx
60mm
30 mm
х
90 mm
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у х dx 60mm 30 mm х 90 mm

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Step 2

The moment of inertia about the x axis can be calculated as,

Tel
Yel = 60
3
dA 60 da
60% dz
dī-
12
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Tel Yel = 60 3 dA 60 da 60% dz dī- 12

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Step 3

Substituting the values in ...

60 dz
(60 (60 da)
2
12
dI( 22400x 234000) dx
Integrating the above we get,
06
20
-
2400 234000 dr
3
I 12.96 x 106 mm2
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60 dz (60 (60 da) 2 12 dI( 22400x 234000) dx Integrating the above we get, 06 20 - 2400 234000 dr 3 I 12.96 x 106 mm2

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