Asked Dec 9, 2019

Cliff divers in acapulco dive into the ocean from h=35m high cliffs. The divers are moving 26 m/s downward in the vertical direction. They travel in a straight line over a distance of 4m through the water before momentarily coming to a rest. Assuming the diver jumps with an initial horizontal velocity of 3.5 m/s. What is the magnitude of the net force on a 70 kg diver?


Expert Answer

Step 1

Given data:

Initial vertical velocity of the diver, uy = 26 m/s

Height of the cliff, H = 35 m

Acceleration due to gravity, g = 9.8 m/s2.

Let the velocity of diver be vy, when it hit the water.

Step 2

Using the second equation of kinematics:


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v,² = u,² +2gH +2gH -V(26)* - +2x9.8×35 = 36.90 m/s

Step 3

The calculation of the  deaccelera...


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U = v, = 36.90 m/s v = 0 s = 4 m


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