Commercial hydrochloric acid is 12.1 M. What volume of commercial HCI solution should be used to prepare 250.0 mL of 3.00 M HCI?

Q: What volume of 3.63 M HCIag) is needed to make 350.0 mL of a 0.169 M hydrochloric acid solution?

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Q: You wish to make a 0.354 M hydroiodic acid solution from a stock solution of 12.0 M hydroiodic acid.…

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Q: What volume (mL) of a 0.0833 M CuSO4 x 5 H2O solution is needed to prepare 250.00 mL of a 0.00422 M…

A: Since the moles of CuSO4X5H2O should be same in both the solutions as we are taking CuSO4X5H2O from…

Q: How many liters of a 4.05 M KNO3 solution can be prepared from 40.9 g of KNO3?

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Q: You have 15 mL of a 0.25 M NaCl(aq) solution. What volume should you dilute it to in order to obtain…

A: Given: The initial volume (V1) of NaCl (sodium chloride) solution is 15 mL The initial molarity (M1)…

Q: You wish to make a 0.399 M nitric acid solution from a stock solution of 6.00 M nitric acid. How…

A: The process of dilution is defined as the process in which a solution with a lower concentration is…

Q: A laboratory assistant needs to prepare 300. mL of 0.185 M CaCl2 solution. How many grams of calcium…

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Q: How many grams of KOH are needed to make 510. mL of a solution that is 0.540 M? A) 0.341 g B) 6.82 g…

A: We know that,. Molarity is the number of moles of solute dissolve in one litre of solution. So,

Q: What volume of 0.175 M sodium phosphate, Na3PO4, solution is necessary to completely react with 95.4…

A: Reaction                              Na3PO4 (aq) + CuCl2 (aq) -------> Cu3(PO4)2 (s) + NaCl (aq)…

Q: A solution of HCl was prepared from a stock solution as follows: 50.00 mL of stock solution was…

A: Given: Volume of stock solution used = 50.00 mL Volume of dilution A prepared = 250.0 mL Volume of…

Q: You wish to make a 0.149 M hydrochloric acid solution from a stock solution of 6.00 M hydrochloric…

A: Calculate the number of moles of HCl in the final dilute solution of 0.149 M and 50.0 milliliters.

Q: In the laboratory, a student adds 57.5 mL of water to 15.1 mL of a 0.508 M nitric acid solution.…

A: Given that 57.5 m L of water is added to 15.1 m L water. Then, the final volume of the diluted…

Q: A student pipets 11 mL of a 0.0155 M solution of CaCl2 into a 100.00 mL volumetric flask and dilutes…

A: Given,

Q: If you wish to prepare a 1.20 M solution of NaNO3, to what volume (in liters) would you have to…

A: Since we are diluting the solution by adding water only Hence the moles of solute NaNO3 will be same…

Q: You wish to make a 0.273 M perchloric acid solution from a stock solution of 3.00 M perchloric acid.…

A: Given information is,

Q: You wish to make a 0.192 M perchloric acid solution from a stock solution of 12.0 M perchloric acid.…

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Q: How much solvent must be added to 25.0 mL of a 10.0 M HBr(aq) solution to form a 4.00 M HBr(aq)…

A: Let V Volumn is added

Q: _____% by mass

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Q: A laboratory assistant needs to prepare 345 mL of 0.180 M CaCl2 solution. How many grams of calcium…

A: Given : concentration of CaCl2 = 0.180 M And volume of solution = 345 mL = 0.345 L…

Q: The concentration of 158 mL of an aqueous solution of KNO2 is 3.56 M. How many grams of KNO2 are…

A: Number of moles of solute present in 1 liter of solution is known as molarity of the solution.

Q: In the laboratory a student combines 46.6 mL of a 0.307 M iron(III) fluoride solution with 22.4 mL…

A: GIVEN: The Volume of Iron(III) Fluoride = 46.6 mL The concentration of Iron(III) Fluoride =0.307 M…

Q: What volume of a 0.351 M perchloric acid solution is required to neutralize 20.3 mL of a 0.171 M…

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Q: a forensic chemist prepares 290.0 mL of a 0.649 M solution from a 4.04 M stock solution. what volume…

A: Molarity is the unit of concentration of a solution, and its unit is mol/L. It is defined by the…

Q: You wish to make a 0.338 M hydrochloric acid solution from a stock solution of 12.0 M hydrochloric…

A: Concentrated solutions upon addition of water gets diluted to lower concentrations. The dilution of…

Q: How many milliliters of a 6.00M NaOH solution are needed to provide 0.350 mil of NaOH?

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Q: What mass of oxalic acid dihydate, H2C2O42H2O, is needed to make a 0.498 mol solution of oxalic acid…

A: Given, Number of mol H2C2O4.2H2O = 0.498 mol Volume = 250.0 mL Since, 1000 mL = 1 L  or        1 mL…

Q: What is the molarity of the final solution when 255 mL of water are added to 0.550 L of a 2.50 M…

A: Given:Initial concentration M1 = 2.50 MInitial volume V1 = 0.550 L.Final volume V2 = 0.550 L + 255…

Q: What volume of 6.0 M NaOH (molar mass = 40.0 g/mol) is needed to prepare 100 ml of 1.0 M NaOH?

A: The given problem relates to stock dilution, so we can use the stoichiometric relation to calculate…

Q: How many liters of a 8.30 M KNO3 solution can be prepared from 72.8 g of KNO3?

A: Calculate number of moles of KNO3:

Q: How many mL of water should be added to 50.0 mL of a 15.0 M H 2SO 4 solution to give a final…

A:

Q: A mixture of hydrochloric and sulfuric acids is prepared so that it contains 0.575 M HCl and 0.145 M…

A: The moles of HCl and sulfuric acid is calculated.

Q: What is molar concentration of a 350 mL solution that contains 10.5 g of NaOH? Determine the volume…

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Q: A laboratory custodian needed to prepare 4590 mL of a 2.45 N solution of HCl for the conduct of…

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Q: What mass of oxalic acid dihydate, H2C2O4•2H2O, is needed to make a 0.498 M solution of oxalic acid…

A:

Q: You wish to make a 0.315 M perchloric acid solution from a stock solution of 12.0 M perchloric acid.…

A: Given, the concentration of stock solution =12.0 Mconcentration of diluted solution =0.315 Mvolume…

Q: A student pipets 18 mL of a 0.0459 M solution of CaCl2 into a 100.00 mL volumetric flask and dilutes…

A: Given  Initial Volume of solution ( V1 ) = 18 mL  Molarity ( M1 ) = 0.0459 M  Final Volume of…

Q: How many milliliters of 10.5 M HCI(aq) are needed to prepare 690.0 mL of 1.00 M HCI(aq)?

A: Solution In chemistry, the concentration of answer|an answer} is that the amount of a substance…

Q: mass of zinc hydroxide

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Q: If 74.3 mL of 0.777 M HCl is diluted to a total volume of 152 mL and then 25.0 mL of the diluted HCl…

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Q: Consider the reaction: 2 NaBH4(aq) + H2SO4(aq) → 2 H2(g) + Na2SO4(aq) + B2H6(g) What volume, in mL,…

A: Given, From the equation, it is clear that two equivalences of NaBH4 produce one equivalence of…

Q: A l1.5 g sample of an aqueous solution of hydroiodic acid contains an unknown amount of the acid. If…

A: Given, Mass of Mixture = 11.5 g Molarity of NaOH = 0.898 M = 0.898 mol/L Volume of NaOH = 12.2 mL =…

Q: What volume of 0.36 mol/L sodium hydroxide solution can be prepared from 85.0 ml of a 6.5 mol/L…

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Q: You wish to make a 0.421 M hydroiodic acid solution from a stock solution of 3.00 M hydroiodic acid.…

A: Dilution of the solution: On dilution of the solution with pure water, the mole of solute remains…

Q: How many grams of KNO3 will be required to prepare 800 mL of 1.40 M KNO3?

A: Molarity = number of moles of solute/volume of solution (in L)  so, moles = molarity × volume (in L)…

Q: What is the initial volume, in milliliters, needed to prepare 100. mL of 6.00 M HNO3 from 18.0 M…

A: The molarity of a solution is the number of moles of a substance present in 1 litre of its solution.…

Q: How many milliliters of 10.0 M HC1(aq) are needed to prepare 580.0 mL of 1.00 M HCI(aq)? % = ml

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Q: In the laboratory a student combines 34.4 mL of a 0.228 M cobalt(II) chloride solution with 23.9 mL…

A: Calculate the number of moles of present in cobalt(II) chloride solution: 1 mL = 0.001 L One mole…

Q: You wish to make a 0.184 M hydroiodic acid solution from a stock solution of 3.00 M hydroiodic acid.…

A: Relationship between the Initial and Final Volume to the Initial and Final Molarity is as given…

Q: A student wants to make a 1.600 M aqueous solution of barium sulfate, BasO4, and has a bottle…

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Solutions

Solutions can be considered as homogeneous mixtures which contain two or more than two chemical substances. The chemical substance which is the greater part is defined as solvent. And the chemical substance that is dissolved in a solvent is referred to as solute. Solution chemistry plays an important role in chemistry since it supports many commercial applications of solutions.