Compound C has a molecular ion in its mass spectrum at 146 and a prominent absorption in its IR spectrum at 1762 cm. C shows the following 'H NMR spectral data: 1.47 (doublet, 3 H), 2.07 (singlet, 6 H), and 6.84 (quartet, 1 H) ppm. What is the structure of C?
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- Compound C has a molecular ion in its mass spectrum at 146 and a prominent absorption in its IR spectrum at 1762 cm-1. C shows the following 1H NMR spectral data: 1.47 (doublet, 3 H), 2.07 (singlet, 6 H), and 6.84 (quartet, 1 H) ppm. What is the structure of C?Reaction of butanenitrile (CH3CH2CH2CN) with methylmagnesium bromide (CH3MgBr), followed by treatment with aqueous acid, forms compound G. G has a molecular ion in its mass spectrum at m/z = 86 and a base peak at m/z = 43. G exhibits a strong absorption in its IR spectrum at 1721 cm−1 and has the 1H NMR spectrum given below. What is the structure of G?Propose a structure for a compound of molecular formula C7H14O2 with an IR absorption at 1740 cm−1 and the following 1H NMR data:
- Reaction of tert-butyl pentyl ether [CH3CH2CH2CH2CH2OC(CH3)3] with HBr forms 1-bromopentane (CH3CH2CH2CH2CH2Br) and compound B. B has a molecular ion in its mass spectrum at 56 and gives peaks in its IR spectrum at 3150−3000, 3000−2850, and 1650 cm−1. Propose a structure for B, and draw a stepwise mechanism that accounts for its formation.Compound C has molecular formula C5H8O. The IR, mass, 1H-NMR, and 13C-NMR spectra are shown below. Suggest a structure for C and explain your reasoning.Compound A has molecular formula C5H10O. It shows three signals in the 1H-NMR spectrum - a doublet of integral 6 at 1.1 ppm, a singlet of integral 3 at 2.14 ppm, and a quintet of integral 1 at 2.58 ppm. Suggest a structure for A and explain your reasoning.
- 15. Compound C has a molecular weight of 94.54 and the 1H-NMR spectrum shows four signals - a triplet at 3.81 ppm, a triplet at 3.63 ppm, a singlet at 2.19 ppm, and a triplet of triplets at 2.02 ppm. The mass, IR, and 13C-NMR spectra of compound C are shown below, they are also downloadable for closer inspection by clicking the link under the spectral data. Identify C and explain your reasoning. refer to pictureCompound A with molecular formula C6H10 has two peaks in its 1H NMR spectrum, both of which are singlets (with ratio 9 : 1). Compound A reacts with an acidic aqueous solution containing mercuric sulfate to form compound B, which gives a positive iodoform test and has an 1H NMR spectrum that shows two singlets (with ratio 3 : 1). Identify A and B.Compounds B and C are isomers with molecular formula C5H9BrO2. The 1H NMR spectrum of compounds B and C are shown below. The IR spectrum corresponding to compound B showed strong absorption bands at 1739, 1225, and 1158 cm-1, while the spectrum corresponding to compound C have strong bands at 1735, 1237, and 1182 cm-1. 1.Based on the information provided, determine the structure of compounds B and C. 2.Assign all peaks in 1H NMR spectrum of compounds B and C.
- In the presence of a small amount of acid, a solution of acetaldehyde (CH3CHO) in methanol (CH3OH) was allowed to stand and a new compound L was formed. L has a molecular ion in its mass spectrum at 90 and IR absorptions at 2992 and 2941 cm−1. L shows three signals in its 13C NMR at 19, 52, and 101 ppm. The 1H NMR spectrum of L is given below. What is the structure of L?Propose a structure of compound C (molecular formula C10H12O) consistent with the following data. C is partly responsible for the odor and flavor of raspberries. Compound C: IR absorption at 1717 cm-1Treatment of compound D with LiAlH4 followed by H2O forms compound E. D shows a molecular ion in its mass spectrum at m/z = 71 and IR absorptions at 3600–3200 and 2263 cm–1. E shows a molecular ion in its mass spectrum at m/z = 75 and IR absorptions at 3636 and 3600–3200 cm–1. Propose structures for D and E from these data and the given 1H NMR spectra.