Question
Asked Nov 1, 2019
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Compute the binding energy per nucleon for H (whose atom has a measured mass of 3.016050 u)
3He (3.016029 u),JHe (4.002603 u), Li (6.015123 u), and 3Li (7.016004 u). Note how extraordinarily
strongly bound the average nucleon in 4He is compared to its neighboring nuclei. Describe some
the advantages that4He has over its neighbors that might explain its exceptionally tight binding
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Compute the binding energy per nucleon for H (whose atom has a measured mass of 3.016050 u) 3He (3.016029 u),JHe (4.002603 u), Li (6.015123 u), and 3Li (7.016004 u). Note how extraordinarily strongly bound the average nucleon in 4He is compared to its neighboring nuclei. Describe some the advantages that4He has over its neighbors that might explain its exceptionally tight binding

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Expert Answer

Step 1

The mass defect (Δm) is calculated using equation (1) in which m is the given mass of atom, p is the number protons, n is the number of neutrons, e is the number of electrons, mp is the mass of proton, mn is the mass of neutron and me is the mass of electron. The mass defect for 31H is calculated as follows:

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Дт %3D (рт, + пт, + ет,) - т Дт(;H)3D[(1x1.007276 amu) + (2х1.008665 amu)+ (1x0.000549 аmu)]-3.016050 amu (1) 3D 0.009105 аmu

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Step 2

The binding energy per nucleon (BEn) for 31H is calculated using equation (2) in which A is the number of nucleons.

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1 BE Amx931 MeV/amux- 1 BE CH) 0.009105 amux 931 MeV/amux- 3 nucleons =2.826 MeV/mucleon

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Step 3

Similarly, the mass defect and the binding energy for 3...

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AmGHe) [(2x1.007276 amu)+(1x1.008665 amu)+(2x0.000549 amu)]-3.016029 amu 0.008286 amu 1 He) 0.008286 amu x 931 MeV/amu x BE 3 nucleons = 2.571 MeV/nucle on

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