Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN: 9781285741550
Author: James Stewart
Publisher: Cengage Learning
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**Problem Statement: Compute the Dot Product**

Given two vectors, calculate their dot product.

Vectors:
\[ (\mathbf{i} + \mathbf{j}) \cdot (\mathbf{j} + \mathbf{k}) \]

*Please enter your answer in the provided input box.*

**Explanation:**
To compute the dot product, follow these steps:
1. Multiply the corresponding components of the vectors.
2. Add up all the products obtained.

The dot product formula for two vectors \(\mathbf{a} = a_1\mathbf{i} + a_2\mathbf{j} + a_3\mathbf{k}\) and \(\mathbf{b} = b_1\mathbf{i} + b_2\mathbf{j} + b_3\mathbf{k}\) is calculated as follows:
\[ \mathbf{a} \cdot \mathbf{b} = (a_1 \cdot b_1) + (a_2 \cdot b_2) + (a_3 \cdot b_3) \]

In this specific problem, expand the vectors and compute the products accordingly:
\[ (\mathbf{i} + \mathbf{j}) \cdot (\mathbf{j} + \mathbf{k}) \]

Now, apply distributive property:
\[ \mathbf{i} \cdot \mathbf{j} + \mathbf{i} \cdot \mathbf{k} + \mathbf{j} \cdot \mathbf{j} + \mathbf{j} \cdot \mathbf{k} \]

Remember:
- \(\mathbf{i} \cdot \mathbf{i} = 1\)
- \(\mathbf{j} \cdot \mathbf{j} = 1\)
- \(\mathbf{k} \cdot \mathbf{k} = 1\)
- \(\mathbf{i} \cdot \mathbf{j} = 0\)
- \(\mathbf{i} \cdot \mathbf{k} = 0\)
- \(\mathbf{j} \cdot \mathbf{k} = 0\)

Combine all the results to find the final dot product value.
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Transcribed Image Text:**Problem Statement: Compute the Dot Product** Given two vectors, calculate their dot product. Vectors: \[ (\mathbf{i} + \mathbf{j}) \cdot (\mathbf{j} + \mathbf{k}) \] *Please enter your answer in the provided input box.* **Explanation:** To compute the dot product, follow these steps: 1. Multiply the corresponding components of the vectors. 2. Add up all the products obtained. The dot product formula for two vectors \(\mathbf{a} = a_1\mathbf{i} + a_2\mathbf{j} + a_3\mathbf{k}\) and \(\mathbf{b} = b_1\mathbf{i} + b_2\mathbf{j} + b_3\mathbf{k}\) is calculated as follows: \[ \mathbf{a} \cdot \mathbf{b} = (a_1 \cdot b_1) + (a_2 \cdot b_2) + (a_3 \cdot b_3) \] In this specific problem, expand the vectors and compute the products accordingly: \[ (\mathbf{i} + \mathbf{j}) \cdot (\mathbf{j} + \mathbf{k}) \] Now, apply distributive property: \[ \mathbf{i} \cdot \mathbf{j} + \mathbf{i} \cdot \mathbf{k} + \mathbf{j} \cdot \mathbf{j} + \mathbf{j} \cdot \mathbf{k} \] Remember: - \(\mathbf{i} \cdot \mathbf{i} = 1\) - \(\mathbf{j} \cdot \mathbf{j} = 1\) - \(\mathbf{k} \cdot \mathbf{k} = 1\) - \(\mathbf{i} \cdot \mathbf{j} = 0\) - \(\mathbf{i} \cdot \mathbf{k} = 0\) - \(\mathbf{j} \cdot \mathbf{k} = 0\) Combine all the results to find the final dot product value.
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