Consider a place where the gravity is 4 times the gravity on Earth (g' = 4g), then the frequency of oscillation of a simple pendulum in that place, f, as compared to its frequency on earth is: f = 4f O f- 2f O f-f/2 O f=f/3

Consider a place where the gravity is 4 times the gravity on Earth (g' = 4g), then the frequency of oscillation of a simple pendulum in that place, f, as compared to its frequency on earth is: f = 4f O f- 2f O f-f/2 O f=f/3

Name: Consider a place where the gravity is 4 times the gravity on Earth (g
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Description: Consider a place where the gravity is 4 times the gravity on Earth (g' = 4g), thenthe frequency of oscillation of a simple pendulum in that place, f, as comparedto its frequency on earth isO f- 4fO f- 2fO r-f/2Or-t/3

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter16: Oscillations

Section: Chapter Questions

Problem 34PQ: Show that angular frequency of a physical pendulum phy=mgrCM/I (Eq. 16.33) equals the angular...

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