# Consider a source of light with wavelength λ = 510 nm that shines on two identical narrow slits. The slits are separated by a distance a = 30 μm. An interference pattern is observed on a screen located a distance L away from the slits. On the screen, the location of the second dark spot to the left of the central bright spot is found to be y = 1.2 cm from the central bright spot. Let this particular position on the screen be referred to as P1.A. Light from both slits travels to the point P1. How much further does the light from one slit travel compared to the light from the other slit?distance = _____ nmB. The path difference in part A is equal to a·sinθ where the angle θ is the separation between the central bright spot and the second dark spot. What is this angle θ?θ = _____ °C. Using the angle θ and the location y of the second dark spot on the screen, determine the distance L between the slits and the screen.L =  _____ m

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Consider a source of light with wavelength λ = 510 nm that shines on two identical narrow slits. The slits are separated by a distance a = 30 μm. An interference pattern is observed on a screen located a distance L away from the slits. On the screen, the location of the second dark spot to the left of the central bright spot is found to be y = 1.2 cm from the central bright spot. Let this particular position on the screen be referred to as P1.

A. Light from both slits travels to the point P1. How much further does the light from one slit travel compared to the light from the other slit?
distance = _____ nm

B. The path difference in part A is equal to a·sinθ where the angle θ is the separation between the central bright spot and the second dark spot. What is this angle θ?
θ = _____ °

C. Using the angle θ and the location y of the second dark spot on the screen, determine the distance L between the slits and the screen.
L =  _____ m

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Step 1

(a)

The distance travelled by the light from one slit compared to the light from the other is

Step 2

For the second bright spot, n=1. Then the equation (I) becomes

Step 3

Substituting the value f...

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