Question
Asked Feb 13, 2020
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Consider the collection of nonmetallic elements O, P, Te,
I, and B. (a) Which two would form the most polar single
bond? (b) Which two would form the longest single bond?
(c) Which two would be likely to form a compound of formula
XY2? (d) Which combinations of elements would likely
yield a compound of empirical formula X2Y3?

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Expert Answer

Step 1

(a)The most polar bond would be formed between the atoms that have highest electronegativity difference. The bond between a metal and non-metal will be highly polar because a metal is electropositive and a non-metal is electronegative.

From the given atoms, only boron (B) is a metal. From the non-metals, O is most electronegative, hence the bond between B and O would be most polar single bond.

Step 2

(b) The atoms that have largest atomic radii would form the longest single bond.  Atomic radius of B is 0.84A0, that of O is 0.66 A0, that of P is 1.01 A0, that of Te is 1.38 A0 and that of I is 1.39 A0.

It means the distance between the atoms Te and I is largest and they will form the largest single bond.

Step 3

(c) The formula XY2 means one of the atoms would have +2 oxidation state and the other has -1 oxidation state.

The halogens that belong to group 7A need one electron to complete their octet and hence, have an oxidation state of -1.  As I is a halogen, it is the atom that would have -1 oxidat...

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