Consider the following code and write the output of this code?
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Consider the following code and write the output of this code?
int **p;
p = new int* [5];
for (int i = 0; i < 5; i++)
p[i] = new int[3];
for (int i = 1; i < 5; i++)
for (int j = 0; j < 3; j++)
p[i][j] = 2 * i + j;
for (int i = 1; i < 5; i++)
{
for (int j = 0; j < 3; j++)
cout << p[i][j] << " ";
cout << endl;
}
Step by step
Solved in 2 steps
- a) Consider the following code and write the output of this code? int **p;p = new int* [5];for (int i = 0; i < 5; i++)p[i] = new int[3];for (int i = 1; i < 5; i++) for (int j = 0; j < 3; j++)p[i][j] = 2 * i + j;for (int i = 1; i < 5; i++){for (int j = 0; j < 3; j++)cout << p[i][j] << " ";cout << endl;}b) What is wrong with the following code?int *p; //Line 1int *q; //Line 2p = new int [5]; //Line 3*p = 2; //Line 4for (int i = 1; i < 5; i++) //Line 5p[i] = p[i-1] + i; //Line 6q = p; //Line 7delete [] p; //Line 8for (int j = 0; j < 5; j++) //Line 9cout << q[j] << " "; //Line 10cout << endl; //Line 11Consider the following array: int[] a = { 1, 2, 3, 4, 5, 4, 3, 2, 1, 0 };What are the contents of the array a after the following loops complete?a. for (int i = 1; i < 10; i++) { a[i] = a[i - 1]; } b. for (int i = 9; i > 0; i--) { a[i] = a[i - 1]; }c. for (int i = 0; i < 9; i++) { a[i] = a[i + 1]; }d. for (int i = 8; i >= 0; i--) { a[i] = a[i + 1]; }e. for (int i = 1; i < 10; i++) { a[i] = a[i] + a[i - 1]; }f. for (int i = 1; i < 10; i = i + 2) { a[i] = 0; }g. for (int i = 0; i < 5; i++) { a[i + 5] = a[i]; }h. for (int i = 1; i < 5; i++) { a[i] = a[9 - i]; }Consider the following array: int a[ ] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 0}; What are the contents of the array after the following loops complete? for (int i = 1; i < 10; i++) { a[i] = a[i– 1]; } for (int i = 9; i > 0; i--) { a[i] = a[i – 1]; } for (int i = 0; i < 9; i++) { a[i] = a[i + 1]; } for (int i = 8; i >= 0; i--) { a[i] = a[i + 1]; } for (int i = 1; i < 10; i++) { a[i] = a[i ] + a[i– 1]; } for (int i = 1; i < 10; i = i + 2) { a[i] = 0;} for (int i = 0; i < 5; i++) { a[i + 5] = a[i]; } for (int i = 1; i < 5; i++) { a[i] = a[9 - i]; } a[0] a[1] a[2] a[3] a[4] a[5] a[6] a[7] a[8] a[9] a b c d e f g h
- Implement the vacuum cleaning agent function in Python/Java for the scenario described below: Consider two-dimensional Boolean array of size m x n (m and n can each be equal to 4) where m is the number of rows, and n is the number of columns. Obtain numerical positive integer values for m and n as inputs from the user. Generate random numbers and scale them down to either a “0” or a “1” according to whether they represent “Clean” or “Dirty”, respectively. After filling the array with 0s or 1s, start at some random array position indicating the initial position of the vacuum cleaner. First check if at that current position, there is the presence of a “Dirt” or not determined by whether 0 or 1 is filled in at that initial position of the vacuum cleaner. If there is a “Dirt”, clean it, and if there is no “Dirt” do a No-operation. After this is done, generate random numbers modulo 4 to obtain random numbers 0, 1, 2, 3 indicating whether to take a left, right, up or down correspondingly. If…(JAVA)Consider this code: int m = 3; int n = -2; m = ++m * n--; What are the final values of m and n?Write a java code for the following. Write two methods that return the union and intersection of two arrays of integers using the following header: public int [ ] union(int arr1[ ], int arr2[ ] ) public int [ ] intersection(int arr1[ ], int arr2[ ]) For example, the union of two array lists {2, 3, 1, 5} and {3, 4, 6} is {2, 3, 1, 5, 3, 4, 6} and intersection is {3}. Write a test program that prompts the user to enter two lists of size 4 each, and displays their union and intersection. The numbers are separated by exactly one space in the output.
- Give the output from this code fragment: int *p1, *p2; p1 = new int; p2 = new int; *p1 = 10; *p2 = 20; cout << *p1 << “ “ << *p2 << endl; *p1 = *p2; cout << *p1 << “ “ << *p2 << endl; *p1 = 30; cout << *p1 << “ “ << *p2 << endl;What is wrong with the following code? int *p;. //Line 1int *q;. //Line 2 p = new int [5];. //Line 3 *p = 2; //Line 4 for (int i = 1; i < 5; i++). //Line 5p[i] = p[i-1] + i;. //Line 6 q = p;. //Line 7 delete [] p; //Line 8 for (int j = 0; j < 5; j++) //Line 9 cout << q[j] << " "; //Line 10 cout << endl; //Line 11Answer the given question with a proper explanation and step-by-step solution. In Java, please. Consider the following problem. Input: an array of integers A[] Output: rearranges the array to have the following property: Suppose the first element in the original array A[], A[0] = x. In the rearranged array, suppose that x is at index i, that is A[i] = x. Then, we want the rearranged array to be such that A[j] <= x for all j < i and A[j] > x for all j > i. The rearranging should place all the values less than (or equal to) x to the "left" of x and all values larger than x to the right of x. Here's an example. Suppose the array has the elements in this initial order: 4 3 9 2 7 6 5 A[0] = 4. After rearranging elements, we get: 3 2 4 5 9 7 6 That is, A[0] = 4, is positioned in the resulting array so that all elements less than 4 (that is, 2, 3) are to its left (in no particular order), and all elements larger than 4 are to its right (again, in no particular order).
- Explain this C code line per line please #include <stdio.h> #include <malloc.h> void printArray(int**, int); int main() { int i = 0, j = 0, n = 5; int **arr = (int**)malloc(n * sizeof(int*)); for(int i=0;i<n;i++){ *(arr+i) = (int*)malloc(n*sizeof(int)); } for(i=0;i<n;i++){ for(int j=0;j<n;j++){ *(*(arr+i) + j) = 0; } } printArray(arr, n); for(i=0;i<n;i++){ *( *(arr + i) + i) = i+1; } printArray(arr,n); return 0; } void printArray(int ** array, int size) { int i,j; for(i = 0;i<size;i++){ for(j=0;j<size;j++){ printf("%d ", *( *(array + i) + j)); } printf("\n"); } printf("\n"); }given the declaration int[]n={1,2,3,4,5}; what is the value of n[4]?Write a Java function called SpOdd, so that this function would take an array of integers as input and return an array of integers with all the odd numbers in the original array. Make sure to keep the same order as the original array and also test your function in the main function. Sample output of the main function: The original Array: [3, 8, 5, 7, 1, 9, 2] The odd elements in the array: [3, 5, 7, 1, 9]