Consider the following code snippet: int sum = 0; int mylist[] = {8, 12, 3, 4, 12, 9, 8}; for (int row = 0; row < mylist.length; ++row) { for (int col = 0; col < mylist.length; ++col) { mylist[row][col] = row * col ; } What is wrong? O mylist is not a 2D array, so two subscripts are not allowed O It has an infinite loop O The inner for loop should be for ( col = 0; col < mylist[row].length; col ++) O The initialization of an array cannot occur on the same line as the array declaration. These must be separate statements.

Java Program Requirements: Create a DodecahedronList class that stores the name of the list and an ArrayList of Dodecahedron objects. It also includes methods that return the name of the list, number of Dodecahedron objects in the DodecahedronList, total surface area, total volume, average surface area, average volume, and average surface to volume ratio for all Dodecahedron objects in the DodecahedronList. The toString method returns a String containing the name of the list followed by each Dodecahedron in the ArrayList, and a summaryInfo method returns summary information about the list. Design: The DodecahedronList class has two fields, a constructor, and methods as outlined below. (1) Fields (instance variables): a String representing the name of the list and an ArrayList of Dodecahedron objects. These are the only fields (instance variables) that this class should have. (2) Constructor: Your DodecahedronList class must contain a constructor that accepts a parameter of type String…

The following program generates an error. Why? const int NUM_ELEMENTS 5; vector userVals(NUM_ELEMENTS); unsigned int i3; userVals.at(0) 13; userVals.at(1) = 7; userVals.at(2) 43B %3D for (i = 0; i <= NUM_ELEMENTS; ++i) { %3D cout << userVals.at(i) << endl; O The for loop tries to access an index that is out of the vector's valid range. Variable i is declared as an unsigned integer. The vector userVals has 5 elements, but only 3 have values assigned. O The integer NUM_ELEMENTS is declared as a constant

X42: frontPiece Given an int array of any length, return a new array of its first 2 elements. If the array is smaller than length 2, use whatever elements are present. Examples: frontPiece ({1, 2, 3}) -> {1, 2} frontPiece ({1, 2}) -> {1, 2} Your Answer: Feedback Your feedback will appear here when you check 1 public int[] frontPiece(int[] nums) 2 { your answer. 3 4 }

%matplotlib inlineimport numpy as npfrom matplotlib import pyplot as pltimport math xs = np.array([0.        , 0.01010101, 0.02020202, 0.03030303, 0.04040404,        0.05050505, 0.06060606, 0.07070707, 0.08080808, 0.09090909,        0.1010101 , 0.11111111, 0.12121212, 0.13131313, 0.14141414,        0.15151515, 0.16161616, 0.17171717, 0.18181818, 0.19191919,        0.2020202 , 0.21212121, 0.22222222, 0.23232323, 0.24242424,        0.25252525, 0.26262626, 0.27272727, 0.28282828, 0.29292929,        0.3030303 , 0.31313131, 0.32323232, 0.33333333, 0.34343434,        0.35353535, 0.36363636, 0.37373737, 0.38383838, 0.39393939,        0.4040404 , 0.41414141, 0.42424242, 0.43434343, 0.44444444,        0.45454545, 0.46464646, 0.47474747, 0.48484848, 0.49494949,        0.50505051, 0.51515152, 0.52525253, 0.53535354, 0.54545455,        0.55555556, 0.56565657, 0.57575758, 0.58585859, 0.5959596 ,        0.60606061, 0.61616162, 0.62626263, 0.63636364, 0.64646465,        0.65656566, 0.66666667,…

Bar Graph, v 1.0 Purpose. The purpose of this lab is to produce a bar graph showing the population growth of a city called Prairieville, California. The bar graph should show the population growth of the city in 20 year increments for the last 100 years. The bar graph should be printed using a loop. The loop can be either a while loop or a for loop. Write a program called cityPopulation Graph.cpp to produce the bar graph. Requirements. 1. Use these population values with their corresponding years: 1922, 2000 people 1942, 5000 people 1962, 6000 people 1982, 9000 people 2002, 14,000 people 2012, 15,000 people 2022, 17,000 people 2. For each year, the program should display the year with a bar consisting of one asterisk for each 1000 people. 3. Each time the loop is performed (that is, each time the loop iterates) one of the year values is displayed with asterisks next to it. That is: 1st time loop is performed/iterates the year 1922 and the correct number of asterisks should be…

private Vector location;private Vector velocity;private Vector acceleration;private int lifespan;private static final int MAX_LIFESPAN = 25;private static final int RADIUS = 7; public boolean isAlive() { }   public void update() {//code here} Using java, if particle is alive then add velocity vector to location vector, add acceleration vector to velocity vector, and decrement lifespan by 1. Thank you.

Use € Or € to indicate whether the given object 1s an element of the given set.5 {1,2,3,4,5,6}

#include <iostream>#include <cstdlib>using namespace std; class IntNode {public:   IntNode(int dataInit = 0, IntNode* nextLoc = nullptr);   void InsertAfter(IntNode* nodeLoc);   IntNode* GetNext();   void PrintNodeData();   int GetDataVal();private:   int dataVal;   IntNode* nextNodePtr;}; // ConstructorIntNode::IntNode(int dataInit, IntNode* nextLoc) {   this->dataVal = dataInit;   this->nextNodePtr = nextLoc;} /* Insert node after this node. * Before: this -- next * After:  this -- node -- next */void IntNode::InsertAfter(IntNode* nodeLoc) {   IntNode* tmpNext = nullptr;      tmpNext = this->nextNodePtr;    // Remember next   this->nextNodePtr = nodeLoc;    // this -- node -- ?   nodeLoc->nextNodePtr = tmpNext; // this -- node -- next} // Print dataValvoid IntNode::PrintNodeData() {   cout << this->dataVal << endl;} // Grab location pointed by nextNodePtrIntNode* IntNode::GetNext() {   return this->nextNodePtr;} int IntNode::GetDataVal() {…

For any element in keysList with a value greater than 50, print the corresponding value in itemsList, followed by a comma (no spaces). Ex: If the input is: 32 105 101 35 10 20 30 40 the output is: 20,30, 1 #include 2 3 int main(void) { const int SIZE_LIST = 4; int keysList[SIZE_LIST]; int itemsList[SIZE_LIST]; int i; 4 6 7 8 scanf("%d", &keysList[0]); scanf ("%d", &keysList[1]); scanf("%d", &keysList[2]); scanf("%d", &keysList[3]); 10 11 12 13 scanf ("%d", &itemsList[0]); scanf ("%d", &itemsList[1]); scanf("%d", &itemsList[2]); scanf ("%d", &itemsList[3]); 14 15 16 17 18 19 /* Your code goes here */ 20 21 printf("\n"); 22 23 return 0; 24 }