Question
Asked Oct 2, 2019
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Consider the following compound: Sr3(PO4)2 *4H2O

-Calculate the mass, in grams, of Sr present in 6.39 g of the Sr3(PO4)2 * 4H2O

-Id 6.39 g of the hydrated compound is heated to remove the water, what mass would theoretically remain for the anhydrous salt? 

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oupornd evPO The is Sr(PO4) = u52.8027 H>о e Sv(POH0=4S2.Bo1+ 48)-524a6 glmot The olar mass 18. 015 aol The molar mass The molar mass 87.62 The molav wmass Sr

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86 f Sv3(PO4)2; 4H0 coutain 8162 q of Sr The is calculatid a oltbws Sr in 6 39 Anmount of Sr3(PO20= 87.62 of Sr(PO4)2 0=81.62 7 Sx 524.86 of Sr 524.86 81.62 6.39 of s(P)44,0 11 of Sr 5 24.86 1-067 of Sr

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dehydvatiou o s(PO)4H20 is shonm belon Ss(PO s(POA)) t0olq) The

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