Consider the following hypothesis from a sample of 13 observations that has the value t = 2.78: 3. Ho:u 40 Haiu40 What are the degrees of freedom for this statistic? a. Give the two critical values t* from t Distribution table that bracket t b. Between what two values does the P-value of the test fall? c. Is the value t 2.78 statistically significant at the 5% level? At the 1% level? d. Use Stata to find the exact P-value. What is the Stata command you used to find the exact P e. value?
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- For number 1, Please answer Question 1D only. For number 2, Please answer Question 2D only. For umber 3, Please answer Question 3D only: 3. Consider the following hypothesis from a sample of 13 observations that has the value ? = 2.78: ?0:? = 40 ??:? ≠ 40 a.)What are the degrees of freedom for this statistic? b.)Give the two critical values ?∗ from t Distribution table that bracket t. c.)Between what two values does the P-value of the test fall? d.)Is the value ? = 2.78 statistically significant at the 5% level? At the 1% level? e.)Use Stata to find the exact P-value. What is the Stata command you used to find the exact P- value?If the test of H0: = 19 against Ha: ≠ 19 based on an SRS of 15 observations from a Normal populationproduces the statistic of t = –1.75. The P-value isLet ?1 denote true average tread life for a premium brand of P205/65R15 radial tire, and let ?2 denote the true average tread life for an economy brand of the same size. Test H0: ?1 − ?2 = 5000 versus Ha: ?1 − ?2 > 5000 at level 0.01, using the following data: m = 45, x = 42,100, s1 = 2400, n = 45, y = 36,200, and s2 = 1800.Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.) z = P-value = State the conclusion in the problem context. Fail to reject H0. The data does not suggest that the difference in average tread life exceeds 5000.Reject H0. The data suggests that the difference in average tread life exceeds 5000. Fail to reject H0. The data suggests that the difference in average tread life exceeds 5000.Reject H0. The data does not suggest that the difference in average tread life exceeds 5000.
- Let ?1 denote true average tread life for a premium brand of P205/65R15 radial tire, and let ?2 denote the true average tread life for an economy brand of the same size. Test H0: ?1 − ?2 = 5000 versus Ha: ?1 − ?2 > 5000 at level 0.01, using the following data: m = 45, x = 42,100, s1 = 2400, n = 45, y = 36,200, and s2 = 1800. Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.) z = P-value = State the conclusion in the problem context. Fail to reject H0. The data does not suggest that the difference in average tread life exceeds 5000.Reject H0. The data suggests that the difference in average tread life exceeds 5000. Fail to reject H0. The data suggests that the difference in average tread life exceeds 5000.Reject H0. The data does not suggest that the difference in average tread life exceeds 5000.Consider the following hypothesis test:H 0 : μ = 15H 0 : μ ≠ 15A sample of 50 provided a sample mean of 14.15. The population standard deviation is 3.At 5 percent level of significant, what is your conclusion?Suppose you will perform a test to determine whether there is sufficient evidence to support a claim of a linear correlation between two variables. Find the critical values of r given n = 11 at a significance level of 0.05. ±± 0.575 ±± 0.514 ±± 0.555 ±± 0.602