Consider the following non-homogeneous first-order differential equation, where y = 47 dy dt Ty + y = Kz (t) → z (t) = (+1forto) -1 t<0 y (0) = -10 Find the value of the solution to this equation when y (= 3), or at the third time constant. 7.29 09 06 0 19 O 16

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H4. Consider dt = y² −1, y(0) = yo € R. Solve the differential equation and write the solution as a function of the initial condition yo. Use this information to draw a rough sketch the solution for yo > 1 and yo € (-1,1).