Question
Asked May 17, 2019
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Consider the following procedure: procedure mystery (x, y, z); integer x, y, z;beginz =2; y = z + x;endand consider the following code fragment: A[1] := 2;A[2] := 1;n := 1;mystery (A[1],A[n],n);

What will be the final values of n, A[1] and A[2] if the parameters are passed by reference?

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Expert Answer

Step 1

Call by reference

  • The arguments passed to a function will copy the address of an argument into the formal parameter.
  • Inside the function, the address is used to access the actual argument used in the call.
  • Therefore, the changes made to the parameter will affect the arguments passed.
Step 2

Explanation:

The function “mystery (A[1], A[n], n)” called with arguments (2, 2, 1). The integers in the parameter, x = 2, y = 2, z = 1.

In the begin statement, z becomes 2, y becomes 4.

The parameter changes x = 2, y = 4, z =...

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