Question
Asked Feb 24, 2019
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Number 1

Consider the following reductions and arrange them in order of decreasing
tendency to occur from the given reactions (or lack of reaction) below:
Reductions
1.
Reactions
IrCl63
I. Ir + S → No Reaction
H2S
HCIO2 cr
3. Ir + HC102 → CI. + 1rC163-
4. HCIO + Ce3tNo Reaction
Explain how you arrive at your arrangement.
What substance is the strongest reducing agent?
What substance is the weakest reducing agent?
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Consider the following reductions and arrange them in order of decreasing tendency to occur from the given reactions (or lack of reaction) below: Reductions 1. Reactions IrCl63 I. Ir + S → No Reaction H2S HCIO2 cr 3. Ir + HC102 → CI. + 1rC163- 4. HCIO + Ce3tNo Reaction Explain how you arrive at your arrangement. What substance is the strongest reducing agent? What substance is the weakest reducing agent?

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Expert Answer

Step 1

A reduction reaction involves gain of electron/s. Due to gaining of electron/s, the oxidation number of the molecule, ion or atom decreases.

The general reduction reaction is shown on the white board:

According to the reaction, species A with zero oxidation number (no charge) gains one electron to form A-  which has one negative charge or -1 oxidation number. Here, oxidation number decreases from 0 to -1 thus, species A undergoes reduction.

The order of decreasing tendency of reduction can be explained by analyzing the given reactions.

The given reactions are shown on the white board:

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Step 2

Consider reaction 1 which is shown on the white board.

According to this reaction, Ir and S do not react with each other. This means Ir will not reduce  to H2S and its reduction potential is higher than that of S.

The order is represented on the white board.

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Step 3

Considering the reaction 2 which is shown on the white board.

According to the reaction, F2 is getting reduced to F- due to change of oxidation number from 0 to -1 and Ce3+ is getting oxidized to CeOH3+ due to change i...

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