Question

Step 1

Given equation of parabola y = 7x-x^{2}.

The slope of the tangent line at (x_{1}, y_{1}) is derivative of the given equation y with respect to x at that given point.

Derivative of given equation with respect to x is shown below.

After substituting x = 1 from point (1,6) we get slope of tangent to parabola at (1,6) is 5

Step 2

The point slope form of a straight line with slope m and point (x1, y1) is shown below. Substituting the slope ...

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