Question
Asked Dec 8, 2019
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Consider the region bounded above by f(x)=7x2+3x−45 and below by g(x)=8x2+22x+45. Find the area, in square units, between the two functions.

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Expert Answer

Step 1

The given functions are,

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f(x)=7x +3x-45 and, g(x)= &x² +22x+45 g(x)=&r²

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Step 2

Find the intersect...

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7x? +3х — 45-8x2 + 22х + 45 8x + 22х +45—7х? — Зх + 45 -D0 х* +19х +90— 0 х+10х +9х +90 — 0 x(х +10) +9(х+10) -0 (х+9)(х+10)-0 х%3 —9,—10

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Calculus

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