Censider the remperagture composition diagram shown below for bexane and heptane For he misture of heanen 17 24 9 (MW6.18 gimol and heptanes 30 06 o (MW100.21 gmai what tempeatine wili the miature begnto hol and what is the boliling point of the liquid Sormed by condensation of the vapo?Temperature - composition diagram for a binary miehure ofhaxane (bp= 63 "C) and heptane (bp - 90 "C)9090808070-7060600.10.20.30.40.50.60.70.80.9Mole fraction of heptaneCLA. none of the answersO B. 66 °C and 73 °COC. 70 °C and 78 °CO D.74 °C and 82 °CO E. 77 °C and 84 °COF 68 °C and 76 °CTemperature, "C

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Consider the remperagture composition diagram showe bolow for bexane and heptane For he mituRe of heann 1724 g (MW6.18 gimo end ttanes 30 0 MW-10021 gmal what temperatune wil the muture begjin to hal and what is the boling point of the liquid formed by condensation of the vapo? Temperature - composition diagram for a binary miture of hexane (bp= 63 "C) and heptane (bp-90 "C) 90 90 80 70 70 60 60 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 Mole fraction of heptane Temperature, "C

Consider the remperagture composition diagram showe bolow for bexane and heptane For he mituRe of heann 1724 g (MW6.18 gimo end ttanes 30 0 MW-10021 gmal what temperatune wil the muture begjin to hal and what is the boling point of the liquid formed by condensation of the vapo? Temperature - composition diagram for a binary miture of hexane (bp= 63 "C) and heptane (bp-90 "C) 90 90 80 70 70 60 60 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 Mole fraction of heptane Temperature, "C

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter31: Introduction To Analytical Separations

Section: Chapter Questions

Problem 31.19QAP

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For Indirect Iodometric Analysis of Copper... ~0.0896g KIO3 necessary to consume 350mL of 0.1 M Na2S2O3, Na2S2O3 is stored in an amber glass bottle until ready for use. Primary Standard KIO3 has 2g of KI, 50mL of DI water, and 10 mL of 1.0M HCl is added then immediately titrated with Na2S2O3 until medium yellow or straw... then 5mL of starch indicator is added and titrated again until blue black color turns clear. Unknown CuO use 1.2G of Unknown, 20mL of HNO3 heated until sample dissolved, 25 mL of DI water added and boiled until clear light blue color, after cooling 1:1 NH3 added (~34.47 mL of NH4OH reagent) until permanent deep blue color amine complex, 2g of NH4HF2 added and swirled until dissolved, 3 g of KI is added then titrated immediately with Na2S2O3 until brown color of iodide is nearly gone (brown milk color), 2 g of KSCN and 3 mL of starch indicator is then added with titration continuing until disappearance of new blue black color. 1. Na2CO3 is often added to thiosulfate…
For Indirect Iodometric Analysis of Copper... ~0.0896g KIO3 necessary to consume 350mL of 0.1 M Na2S2O3, Na2S2O3 is stored in an amber glass bottle until ready for use. Primary Standard KIO3 has 2g of KI, 50mL of DI water, and 10 mL of 1.0M HCl is added then immediately titrated with Na2S2O3 until medium yellow or straw... then 5mL of starch indicator is added and titrated again until blue black color turns clear. Unknown CuO use 1.2G of Unknown, 20mL of HNO3 heated until sample dissolved, 25 mL of DI water added and boiled until clear light blue color, after cooling 1:1 NH3 added (~34.47 mL of NH4OH reagent) until permanent deep blue color amine complex, 2g of NH4HF2 added and swirled until dissolved, 3 g of KI is added then titrated immediately with Na2S2O3 until brown color of iodide is nearly gone (brown milk color), 2 g of KSCN and 3 mL of starch indicator is then added with titration continuing until disappearance of new blue black color. 4. Why is the starch indicator solution…
A chemist received different mixtures for analysis with the statement that they contained NaOH, NaHCO3, Na2CO3, or compatible mixtures of these substances, together with inert material. From the data given, identify the respective materials, and calculate the percentage of each component. 1.000g samples and 0.2500N HCl were used in all cases. (A) For Sample W: With PP, 24.32ml was used. A duplicate sample required 48.64ml with MO. (B). For Sample X: The addition of PP caused no color change. With MO, 38.47ml of the acid was required. (C). For Sample Y: To cause a color change in the cold with PP, 15.29ml of the acid was necessary, and an additional 33.19ml was required for complete neutralization. (D) For Sample Z: The sample was titrated with acid until the pink of PP disappeared; this process required 39.96ml. On adding an excess of the acid, boiling, and titrating back with alkali, it was found that the alkali was exactly equivalent to the excess acid added.
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