Consider the two points P1=(-2,4) and P2=(3,-2) in the xy plane.
Find the distance D between P1 and P2
Find the midpoint M between P1 and P2
Write an equation of the circle centered at the midpoint M you found in the previous question and whose radius is so that the points P1 and P2 are on the circle.
Given that two points P (-2,4) and P (3,-2) lies in xy plane
Find the distance D between P1 and P2 as follows.
D (x-x)(y-y (3-(-2)+(-2-4) (3+2)* +(-6)* 2 = 25+36 = V61 = 7.8
Now find the midpoint M between P1 and ...
M +x + y2 2 2 -2+3 4+(-2) 2 2 1 2 2 2 =(0.5,1) The radius of the circle is 3.9 2
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