Constants An iron block with mass ma slides down a frictionless hill of height H. At the base of the hill, it collides with and sticks to a magnet with mass mu- • Part A What is the speed e of the block and magnet immediately after the collision? > View Available Hints) O v- ( ) V29H O v= () V2GH O v= () v2gH O v= (m) 29H O v= () 2gH Submit • Part B Now assume that the two masses continue to move at the speed t trom Part A until they encounter a rough surface. The coeficient of friction between the masses and the surface is u. IH the blocks come to rest after a distance s, which of the following eguations would you use to find a? > View Available ints) () aH = umags o gH = umugs o () 9H = p(mp+ mx)gs o ) 9H = -H(ms+ mM)gs o ) gH = p(mp+ mu)9 Submit

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Chapter6: Momentum, Impulse, And Collisions
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Constants
An iron block with mass mp slides down a frictionless hill of height H. At the base of the hill, it collides with and
sticks to a magnet with mass mM-
Part A
What is the speed v of the block and magnet immediately after the collision?
• View Available Hint(s)
mg+mM
O v=
V29H
тв
mB
O v=
V29H
mg+mM
mB
O v=
V29H
my
mB+mM
O v=
| 2gH
тв
O v=
mB 2gH
Submit
Part B
Now assume that the two masses continue to move at the speed v from Part A until they encounter a rough surface. The coefficient of friction between the masses and the surface is u. If the blocks come to rest after a distance s, which of the following equations would
you use to find s?
• View Available Hint(s)
(mg)
gH = µmBgs
mB+mM
(тв)"
gHμmMgs
mg+mM
(mg)2
gH = µ(mB+ mm)gs
mB+mM
(тв)?
mg+mM
дH %— — и (тв + тм)gs
(тв)?
gH = µ(mB+ mm)g
mB+mM
Submit
Transcribed Image Text:Constants An iron block with mass mp slides down a frictionless hill of height H. At the base of the hill, it collides with and sticks to a magnet with mass mM- Part A What is the speed v of the block and magnet immediately after the collision? • View Available Hint(s) mg+mM O v= V29H тв mB O v= V29H mg+mM mB O v= V29H my mB+mM O v= | 2gH тв O v= mB 2gH Submit Part B Now assume that the two masses continue to move at the speed v from Part A until they encounter a rough surface. The coefficient of friction between the masses and the surface is u. If the blocks come to rest after a distance s, which of the following equations would you use to find s? • View Available Hint(s) (mg) gH = µmBgs mB+mM (тв)" gHμmMgs mg+mM (mg)2 gH = µ(mB+ mm)gs mB+mM (тв)? mg+mM дH %— — и (тв + тм)gs (тв)? gH = µ(mB+ mm)g mB+mM Submit
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