Convert grams of Fe203 to grams of Fe. Select the correct units and conversion factors for each step in the following unit roadmap.Fe2O3(s) + 3 CO(g)2 Fe(s) + 3 CO2(g)g Fe,O,g of Fe159.7 gFe2031mol Fe2032 mol Fe1mol Fe2O32 mol Femol Fe2O31 mol Fe2031mol Fe203159.7 g Fe2031g Fe55.85 mol Fe1g Fe203159.7 mol Fe2031mol Fe55.85 g Fe55.85 g Fe1 mol Fe55.85 mol Femol Femol CO21g FeReset

Given Fe₂O3(s) + 3 CO(g) → 2 Fe(s) + 3CO₂(g) we know a relation which will be used here mass =…

Convert grams of Fe203 to grams of Fe. Select the correct units and conversion factors for each step in the following unit roadmap. Fe2O3(s) + 3 CO(g) 2 Fe(s) + 3 CO2(g) o Fe,O, g of Fe 159.7 g Fe203 1mol Fe203 2 mol Fe 30 1mol Fe2O3 2 mol Fe 1mol Fe203 mol Fe2O3 1g Fe203 1mol Fe203 159.7 g Fe203 1g Fe 55.85 mol Fe 1mol Fe 159.7 mol Fe2O3 55.85 g Fe 55.85 mol Fe 55.85 g Fe mol Fe mol CO2 1mol Fe 1gFe

Convert grams of Fe203 to grams of Fe. Select the correct units and conversion factors for each step in the following unit roadmap. Fe2O3(s) + 3 CO(g) 2 Fe(s) + 3 CO2(g) o Fe,O, g of Fe 159.7 g Fe203 1mol Fe203 2 mol Fe 30 1mol Fe2O3 2 mol Fe 1mol Fe203 mol Fe2O3 1g Fe203 1mol Fe203 159.7 g Fe203 1g Fe 55.85 mol Fe 1mol Fe 159.7 mol Fe2O3 55.85 g Fe 55.85 mol Fe 55.85 g Fe mol Fe mol CO2 1mol Fe 1gFe

Chemistry & Chemical Reactivity

10th Edition

ISBN:9781337399074

Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Chapter18: Principles Of Chemical Reactivity: Entropy And Free Energy

Section: Chapter Questions

Problem 53GQ: About 5 billion kilograms of benzene, C6H6, are made each year. Benzene is used as a starting...

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Given the following data, where did 339 come from? Component Chemical formula Percentage Mass of component Mass of Hydrogen Mass of Carbon Propene C3H6 7% 7 kg =642×7=1 kg=642×7=1 kg =3642×7=6 kg=3642×7=6 kg Propane C3H8 52% 52 kg =844×52=9.45 kg=844×52=9.45 kg =3644×52=42.55 kg=3644×52=42.55 kg Butene C4H8 11.2 11.2 =856×11.2=1.6 kg=856×11.2=1.6 kg =4856×11.2=9.6 kg=4856×11.2=9.6 kg Butane C4H10 29.8 29.8 =1058×29.8=5.14 kg=1058×29.8=5.14 kg =4858×29.8=24.66 kg=4858×29.8=24.66 kg TOTAL =17.19 kg=17.19 kg =82.81 kg=82.81 kg Gross-Calorific value, GCV=339×%C+1427(%H−%O8)+22×%S GCV=339×82.81+1427(17.19−08)+22×0 GCV=52602.72 kJ/kg GCV=52.60272 MJ/kg
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Show work using conversion factors Answer Key:#37a CaCO3 + 2HCl --> CaCl2 + H2O + CO2 #37b 36.46 g/mol HCl #37c 100.09 g/mol CaCO3 #37d 1.250 moles CO2 #37e 4.92 mole HCl #37f 7.1422 moles HCl ( fixed 10/14/2020) #37g 143 g CO2
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