cos(a-B) = Cos A CosB+Sin ASinB 12.

Q: | 4 cos e de = -

A:

Q: (cos(4x))^2=___+____cos=(___x)

A: By double angle formula , we have By taking A=4x, we get

Q: 57. COs cos (A – 50°): = V3 %3D

A:

Q: 311 = Sinx %3D COS

A:

Q: 2. Cos sin

A:

Q: de (sin(0) cos(0)) =

A:

Q: cos 2x-1 i) x sin 2x 2 tan 30–20 ii) tan 40

A: follow next step.

Q: COS X 1. S 7+cos 2x

A:

Q: cos (2x) dx sinx+cosx COS Evaluate:

A: the given integral is: ∫cos(2x)sinx+cosxdx we have to evaluate the given integral.

Q: sin ;cos 3

A: Given: sinπ4=          ……1cos8π3=          ……2

Q: cos 4z - cos 2z =

A: cosx−cosy​=−2sinx+y2sinx−y​2​

Q: Sinx -cos2y=l COS

A: If f(x) and g(x) are the functions of 'x' . Now, differentiate y= f(g(x)) with respect to 'x' , then…

Q: 4) Sec CA-B) = cos CA+B) CoS A - Sin²B

A:

Q: COS M + Sin n 2 secn COS n

A: we can solve by using trigonometric identities  Sin2x+cos2x=1

Q: cos x csc3 x + C sin4 x 1.

A: To evaluate the given integral.

Q: sin 2x cos 2X I+ 3 cos4X

A:

Q: cos x = sin 2x, x I SO 3.

A:

Q: sin7t sin4t dt =- 121 – cos 31) dt A) True B) False

A:

Q: snip

A:

Q: 1- cosx dx A -2/2cos- +C B 2/2cos- +c -2/2 sin-+C 2 D 2/2 sin- +C

A:

Q: I+ Sin2X t Cos 2x COSX

A: Given,           1+sin2x+cos2xcosx

Q: cos (x) 2 %3D X = Submit

A:

Q: Integrate sin (2a)cos (2a)da OS

A:

Q: Verify the identity. cos 2x cos² r - sin? x

A: We have to solve the trigonometry problem

Q: Differentiate

A: Given: the function

Q: Estimate cos E- 0.1) + cos

A: Follow the procedure given below.

Q: sin 5tdt V1+ cos /1+cos5t

A: We need to evaluate ∫sin 5t dt1+cos 5t                                    (1) Let  1+cos 5t = u On…

Q: cos (0) tan (0)+3tan(0)=0

A: cosθtanθ+3tanθ=0

Q: Cos 2x %3D 1-sin 2x

A:

Q: 3t CoS cos ut}

A:

Q: Verify the identity.

A: Given: verify the identity cos3x+cos5xcos3x-cos5x=cotxcot4x we know that…

Q: s cos 3ede CoS |- sinb

A: follow next step

Q: cos° (3x) sin (3x) dr

A: Given data:     The given integral expression is: .   Assume cos(3x)=t, and differentiate it both…

Q: cos 0 = √√2 -|~

A: Let's find angle theta.

Q: Cos 0 do |3| 3 6. 0.

A: ∫06πcosθdθ    = sinθ06π    = sin6π-sin0    = 0 - 0   = 0

Q: 25n B- If cos-1 (cos) = y , Find value of y?

A: B. cos-1cos25π6=y =cos-1cos24+1π6=cos-1cos24π6+π6=cos-1cos4π+π6 cos4π+θ=cosθ =cos-1cosπ6=π6

Q: cos(1339x) cos(1337x)+ sin(1337x) sin(1339x) =?

A:

Q: cos 0 + sin 0 2 COS 0.

A: We use the Pythagorean identity to write the expression using sin only

Q: Cos de 1-Sin e

A: To evaluate: I=∫cos3θ1-sin θdθ=∫cos2θ×cos θ1-sin θdθ=∫(1-sin2θ)cos θ1-sin θdθ=∫(1-sin θ)(1+sin θ)cos…

Q: TI tant@-2 tan Bzl show that 2cose - Cos"B2o

A:

Q: cos –1 (-V)] 2 sec OS

A: Simplification

Q: cos 20 + isin 20 B (cos e + i sin 0) A c (cos0 – isin 0) D cos 20 - isin 20

A: Simply convert the polar form to trigonometric form.

Q: cos e) tan (0) +3tan(0)=0

A:

Q: (* sin - 2y cos )d = 0. dr+2ry cosdy COS

A: Find the attachment

Q: stion Three: If y = sin(x) – sin³ (x). show that y' = cos³(x).

A: We will differentiate the function and use the identity : 1 - sin²(x) = cos²(x)

Q: | sin5 cos cos – dx 3

A: The given integral is ∫sin5x3cosx3dx

Q: cos (x2 + 3x +5 ) COS

A: Solved below

Q: (a) cos (tan (1)) = V2 (b) sin cos 2.

A:

Q: Solve cos x + cos 3x cos 2x = 0 %3D

A:

Confidence Intervals

When we calculate intervals in probability and statistics, it can be simply termed as finding out a confidence interval. The confidence interval is usually calculated from the data set which is observed. The value of the parameter that needs to be calculated is present here only.