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Cream andsmoking an excessive amount of cigarettes3. Video and Computer Games Sixty-nine percent ofU.S. heads of household play video or computer games.Choose 4 heads of household at random. Find theprobability thata. None play video or computer games.b. All four do.Source: www.theesa.com4-38

Question
Cream and
smoking an excessive amount of cigarettes
3. Video and Computer Games Sixty-nine percent of
U.S. heads of household play video or computer games.
Choose 4 heads of household at random. Find the
probability that
a. None play video or computer games.
b. All four do.
Source: www.theesa.com
4-38
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Cream and smoking an excessive amount of cigarettes 3. Video and Computer Games Sixty-nine percent of U.S. heads of household play video or computer games. Choose 4 heads of household at random. Find the probability that a. None play video or computer games. b. All four do. Source: www.theesa.com 4-38

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Step 1

From the provided information, the probability (p) of U.S. heads of household who play video or computer games is 0.69. The number of random trial (n) is 4. The process will follow binomial distribution because the number of observation (n) is fixed and each observation is independent and each represents one of two outcomes that is success or failure. Here the probability of success (p) is 0.69. Consider X be a random variable which represents the number of success. The probability distribution function of binomial distribution can be written as:

P(X=x)'C,(p)' (1-p)
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P(X=x)'C,(p)' (1-p)

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Step 2

a)

The probability that none of them play video o...

P(x 0)C,(0.69)(1-0.69)*
-4x1x0.009
0.0369
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P(x 0)C,(0.69)(1-0.69)* -4x1x0.009 0.0369

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