# Cryolite, Na AlF,(s), an ore used in the production of aluminum, can be synthesized using aluminum oxide.Balance the equation for the synthesis of cryolite.2 Na, AIF, + 9 H,O(g)equation: Al, O,(s) + 6 NaOH(1) + 12 HF(g)If 15.6 kg of Al,03(s), 57.4 kg of NaOH(1), and 57.4 kg of HF(g) react completely, how many kilograms of cryolite willbe produced?kg Na,AIF6mass of cryolite produced:64245.1941937Which reactants will be in excess?O HFO NaOHV Al,O3What is the total mass of the excess reactants left over after the reaction is complete?kgtotal mass of excess reactants:

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Step 1

A balanced chemical equation or reaction is the one in which the total number of atoms for each element in the reactant side (left hand side) is equal to the total number of atoms for each element in the product side (right hand side).

The balanced equation for the synthesis of cryolite can be written as:

Step 2

Given,

Mass of Al2O3 = 15.6 kg = 15600 g     (1 kg = 1000 g)

Mass of NaOH = 57.4 kg = 57400 g

Mass of HF = 57.4 kg = 57400 g

Moles of Al2O3 , NaOH and HF can be calculated as:

Step 3

The reaction is :

Al2O3 (s) + 6 NaOH (l) + 12 HF (g) ⟶ 2 Na3AlF6 + 9 H2O (g)

Stoichiometric molar ratio of Al2O3 : NaOH : HF = 1 : 6 : 12

Actual molar ratio of Al2O3 : NaOH : HF = 152.94 : 1435 : 2870 = 1 : 9.4 : 18.8

Therefore, NaOH and HF are the excess re...

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