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Asked Apr 2, 2019
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Currin ulⅡwa
3
5
8
hi
2
fo
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Currin ulⅡwa 3 5 8 hi 2 fo

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Expert Answer

Step 1

(a) The weight of the elevator is equal to the gravitational force on it. The given weight in the unit of pound (lb) can be converted to Newton (N) as follows.

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Step 2

The work done by the electric motor is equal to the product of force and the displacement. The force applied to lift the elevator is equal in magnitude to the force of gravity on the elevator (which is 8232.5N). Thus, the work done by the motor in the process can be computed as shown below.

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Step 3

Given that the power of the motor is 12.5hp. Power is the work done per unit time and th...

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