Question

Find an equation of the tangent line to the curve at the following point: 

y = 2/ 1 + e-x, (0,1)

Expert Answer

Want to see the step-by-step answer?

Check out a sample Q&A here.

Want to see this answer and more?

Experts are waiting 24/7 to provide step-by-step solutions in as fast as 30 minutes!*

*Response times may vary by subject and question complexity. Median response time is 34 minutes for paid subscribers and may be longer for promotional offers.
Tagged in
Math
Calculus

Differential Equations

Related Calculus Q&A

Find answers to questions asked by students like you.

Q: 1 dx x²/4+x²

A: to evaluate the given integral

Q: If g(a) = f(- 1) and f(x) = 3a + 12a - 7, the formula for g can be found as follows. %3D g(x) = f(- ...

A: Click to see the answer

Q: For the function, find all critical numbers and then use the second-derivative test to determine whe...

A: We have, fx=x3-15x2+63x-6 For critical point of the function fx, the first derivative of the functio...

Q: • Solve for the value of "C" on the given differential equation below. Let y(1)=1 9( y - x² )dx + xd...

A: Click to see the answer

Q: Evaluate the integral sin z cos z dr by: а) , using the substitution u = sin r b) using the substitu...

A: Since you have posted a question with multiple sub-parts, we will solve first three sub-parts for yo...

Q: S(x-1/3 – x²/3) dx

A: The given integration is  I=∫(x-13-x23)dx I=∫x-13dx -∫x23dx

Q: Write an equation of the form y = a sinbx or y= a cosbx to describe the graph below. y = ] 2

A: The graph passes through the origin , so the equation of the graph is of form y=asinbx where a is am...

Q: Given that sec a = -9 and sasn find exact values of the requested trig functions. sin a tan a = csc ...

A: given: secα=-9 π2≤α≤π we have to find the exact values of: (a)sinα      (b)tanα     (c)cscα

Q: Give the starting value a, the growth/decay rate r, and the continuous growth/decay rate k. If there...

A: Continuous Growth and decay: y(t)=aekt             ...(1) Where a = value at the start            k ...