Question
Asked Feb 4, 2020
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Two rods of equal length L = 1.87 m form a symmetric cross. The horizontal rod has a charge of Q = 300.0 C, and the vertical rod a charge of -Q = -300.0 C. The charges on both rods are distributed uniformly along their length. Calculate the potential at the point P at a distance D = 3.05 m from one end of the horizontal rod.

+ + + + + +
+ + + + + +
-D
P.
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+ + + + + + + + + + + + -D P.

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Expert Answer

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Step 1

Given:

the length of rod (L) = 1.87 m

charge on horizontal rod (Q1 ) = 300 C

charge on vertical rod (Q2 ) = -300 C

distance between horizontal plate and point P (D) = 3.05 m

 

Step 2

charge density of rod = Q/L

potential at point P due to horizontal rod is,

Physics homework question answer, step 2, image 1

 

Step 3

distance between any point on rod from point P is hypotenus,

Physics homework question answer, step 3, image 1

 

...

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