Question
Asked Jun 20, 2019
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The figure shows a very large nonconducting sheet that has a uniform surface charge density σ = -3.10 μC/m2; it also shows a particle of charge Q = 6.20 μC, at distance d from the sheet. Both are fixed in place. If d = 24.0 cm, at what (a)positive and (b) negative coordinate on the x axis (other than infinity) is the net electric field of the sheet and particle zero? (c) If d = 95.0 cm, at what coordinate is ?

 

d
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d

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Expert Answer

Step 1

Given:

Charge density, o=-3.10UC/m2 = -3.10x10-C/m2
Charge,Q 6.20HC 6.20 x 10- C
Distance,d 24.0 cm-0.24 m
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Charge density, o=-3.10UC/m2 = -3.10x10-C/m2 Charge,Q 6.20HC 6.20 x 10- C Distance,d 24.0 cm-0.24 m

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Step 2

Calculation:

According to the given conditions the sheet is negatively charged, and the point charge Q is positively charged.

The magnitude of the electric field of the sheet is,

E =
(1)
2E0
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E = (1) 2E0

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Step 3

The magnitude of the electric fie...

ρ
-(2)
E =-
4πε,Τ.
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ρ -(2) E =- 4πε,Τ.

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