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DarianaDeducing a rate law from the change in concentration over timeA chemistry graduate student is studying the rate of this reaction:H2CO, (ag) H20 (ag)+Co, (ag)She fills a reaction vessel with HCO2 and measures its concentration as the reaction proceeds:H,Co3]timeminutes)00.800 M10.0.377 M20.0.246 M300.183 M40.0.146 MUse this data to answer the following questions.rate kWrite the rate law for this reaction.Calculate the value of the rate constant k.?XRound your answer to 2 significant digits. Also besure your answer has the correct unit symbol. DarianaUsing an integrated rate law for a first-order reactionConsider this reaction2HI (g)H (g)+I, (e)At a certain temperature it obeys this rate law.rate (0.00981 s[HI]Suppose a vessel contains HI at a concentration of 0.460 M. Calculate the concentration of HI in the vessel 65.0 seconds later. You may assume no otherreaction is important.Round your answer to 2 significant digits?X

Question
Dariana
Deducing a rate law from the change in concentration over time
A chemistry graduate student is studying the rate of this reaction:
H2CO, (ag) H20 (ag)+Co, (ag)
She fills a reaction vessel with HCO2 and measures its concentration as the reaction proceeds:
H,Co3]
time
minutes)
0
0.800 M
10.
0.377 M
20.
0.246 M
30
0.183 M
40.
0.146 M
Use this data to answer the following questions.
rate k
Write the rate law for this reaction.
Calculate the value of the rate constant k.
?
X
Round your answer to 2 significant digits. Also be
sure your answer has the correct unit symbol.
help_outline

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Dariana Deducing a rate law from the change in concentration over time A chemistry graduate student is studying the rate of this reaction: H2CO, (ag) H20 (ag)+Co, (ag) She fills a reaction vessel with HCO2 and measures its concentration as the reaction proceeds: H,Co3] time minutes) 0 0.800 M 10. 0.377 M 20. 0.246 M 30 0.183 M 40. 0.146 M Use this data to answer the following questions. rate k Write the rate law for this reaction. Calculate the value of the rate constant k. ? X Round your answer to 2 significant digits. Also be sure your answer has the correct unit symbol.

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Dariana
Using an integrated rate law for a first-order reaction
Consider this reaction
2HI (g)H (g)+I, (e)
At a certain temperature it obeys this rate law.
rate (0.00981 s[HI]
Suppose a vessel contains HI at a concentration of 0.460 M. Calculate the concentration of HI in the vessel 65.0 seconds later. You may assume no other
reaction is important.
Round your answer to 2 significant digits
?
X
help_outline

Image Transcriptionclose

Dariana Using an integrated rate law for a first-order reaction Consider this reaction 2HI (g)H (g)+I, (e) At a certain temperature it obeys this rate law. rate (0.00981 s[HI] Suppose a vessel contains HI at a concentration of 0.460 M. Calculate the concentration of HI in the vessel 65.0 seconds later. You may assume no other reaction is important. Round your answer to 2 significant digits ? X

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check_circleAnswer
Step 1

Since there are multiple questions, we will answer only the first one. If you require the answer of the second question, please repost it separately. Thank you.

Step 2

The rate law of a reaction is expressed as:

A B
>C+ D
Rate k [A] [BJb
Where, k rate constant
[A], [B
concentration of reactants
a+b order of the reaction
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A B >C+ D Rate k [A] [BJb Where, k rate constant [A], [B concentration of reactants a+b order of the reaction

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Step 3

Now, we need to find the order of the reaction. This can be done by plotting graphs of time versus concentration. If the time vs [conc] graph gives a straight line, it will be a zero order re...

In [H2CO3
Time
[H2CO3]
1/H2CO3]
0
0.800
-0.223
1.25
0.377
2.652
10
-0.976
20
0.246
-1.402
4.065
30
5.464
0.183
-1.698
40
0.146
-1.924
6.849
time vs [conc]
time vs In [conc]
time vs 1/[conc]
.NK.
50
0.5
0
20
40
60
0
20
40
60
Time
Time
Time
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In [H2CO3 Time [H2CO3] 1/H2CO3] 0 0.800 -0.223 1.25 0.377 2.652 10 -0.976 20 0.246 -1.402 4.065 30 5.464 0.183 -1.698 40 0.146 -1.924 6.849 time vs [conc] time vs In [conc] time vs 1/[conc] .NK. 50 0.5 0 20 40 60 0 20 40 60 Time Time Time

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