
Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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Transcribed Image Text:## Knowledge Check: Measurement Multiplication and Division
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### Question 8
**Instruction**: Decide whether each proposed multiplication or division of measurements is possible. If it is possible, write the result in the last column of the table.
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**Problem Table**
| Proposed Multiplication or Division | Is this possible? | Result |
|------------------------------------------------|-------------------|--------------|
| \(\frac{1.8 \text{ km}}{6.0 \text{ s}} = ?\) | ○ yes | \( 300 \ \dfrac{\text{m}}{\text{s}} \) |
| | ○ no | |
| \((3.0 \ \text{cm}^3) \cdot (8.0 \ \text{cm}^2) = ?\) | ○ yes | |
| | ○ no | |
| \(\frac{60. \ \text{cm}^2}{0.20 \ \text{m}} = ?\) | ○ yes | |
| | ○ no | |
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**Explanation of the Interfaces and Tools**:
- The table includes proposed multiplication or division operations with units.
- Each operation requires a decision on whether it is mathematically and physically possible.
- If yes, the result (including units) should be written in the result column.
- If no, leave the result column blank.
- Select the correct option (yes/no) for each operation.
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**Calculation Explanation**:
1. For \(\frac{1.8 \text{ km}}{6.0 \text{ s}}\):
- Calculation: \(1.8 \text{ km}\) divided by \(6.0 \text{ s}\)
- Convert \(1.8 \text{ km}\) to meters: \(1.8 \text{ km} = 1800 \text{ m}\)
- Result: \(\frac{1800 \text{ m}}{6.0 \text{ s}} = 300 \ \dfrac{\text{m}}{\text{s}}\).
2. For \((3.0 \ \text{cm}^3) \cdot (8.0 \ \text{cm}^2)\):
- Calculation: \(3.0 \ \text{cm}^3\
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