  Decide whether or not the equation has a circle as its graph. If it does, give the centerand the radius. If it does not, describe the graph.2+y^-12x+6y -41Select the correct choice below and, if necessary, fill in the answer boxes to complete your choice.OA. The graph of the equation is a line.O B. The graph of the equation is a point.C. The graph of the equation is a circle with center. (Type an ordered pair.)The radius of the circle is(D. The graph is nonexistent.

Question help_outlineImage TranscriptioncloseDecide whether or not the equation has a circle as its graph. If it does, give the center and the radius. If it does not, describe the graph. 2+y^-12x+6y -41 Select the correct choice below and, if necessary, fill in the answer boxes to complete your choice. OA. The graph of the equation is a line. O B. The graph of the equation is a point. C. The graph of the equation is a circle with center . (Type an ordered pair.) The radius of the circle is ( D. The graph is nonexistent. fullscreen
Step 1

Formula used:

Equation of circle whose centre (h, k) and radius r is

(x - h)2 + (y - k)2 = r2

Step 2

Now given that

x2 + y2 -12x + 6y = -41

Step 3

Now rewrite the above equatio...

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