Question
Asked Sep 13, 2019
36 views

Decide whether or not the equation has a circle as its graph. If it does, give the center and the radius. If it does not, decide the graph. 

x2+y2-10x+6y=-30

check_circle

Expert Answer

Step 1

Consider the given equation.

help_outline

Image Transcriptionclose

x? + у? - 10х + 6у%3D-30

fullscreen
Step 2

In order to check whether the equation has circle as its graph, the equation should be manipulated into the standard form of the circle, that is,

help_outline

Image Transcriptionclose

(x-h)yk) =r2,where (h,k) is the center of the circle and r is the radius

fullscreen
Step 3

This manipulation can be done using th...

help_outline

Image Transcriptionclose

(x2-10x)( +6y)-30 (x-s(5)y3(3)= -30 (x-5)-25+(y+3)-9=-30 (x-5)+(y3)30+34 (x-5'+(y+3)4

fullscreen

Want to see the full answer?

See Solution

Check out a sample Q&A here.

Want to see this answer and more?

Solutions are written by subject experts who are available 24/7. Questions are typically answered within 1 hour.*

See Solution
*Response times may vary by subject and question.
Tagged in

Math

Algebra

Other