Question

Asked Oct 6, 2019

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Prove the following:

For any natural number n, if n 2 + 6 n is an even number, then n is an even number.

Step 1

Consider the following information and prove the following:

Step 2

Prove the above result by contradiction:

Since, if **n ^{2}+6n is an even number then n is an even number**.

Let’s prove this by contradiction.

Let n is an odd number so, n=2k+1

So,

Step 3

This leads us to a contradiction because n2+6n is an even number but from the assumption it came out to be...

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