Describe the relationship of enthalpy, work, and internal energy. Calculate the ∆U for these reactions and determine if these reactions do work on the surroundings. A system releases 125.0 kJ of heat as 100.0 kJ of work is done on the system. Calculate the change in internal energy (in kJ).

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Q: system that is doing work on the surroundings and also gaining heat from surroundings

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A:

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A: Given,Heat gain (Q)=612kJChange in internal energy(∆U)=181kJ

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A: Given:Heat (q) = 50 J        Work (W) = 175 J since, work is done on the system which means energy…

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Q: What is the change in the internal energy of the system if the surroundings releases 300J of heat…

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A: According to the first law of thermodynamics, energy can neither be created nor it can be destroyed…

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A:

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Q: What is the change in internal energy (in J) of a system that absorbs 0.697 kJ of heat from its…

A: This can be done using first law of thermodynamics.

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