Design a combinational circuit with three inputs x, y, z, and three outputs a, b, and c. When the binary input is 0, 1,2, or 3 , the binary output is 1 greater than the input. When the binary input is 4, 5, 6, or 7, the binary output is one less than the input.
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Design a combinational circuit with three inputs x, y, z, and three outputs a, b, and c. When the binary input is 0, 1,2, or 3 , the binary output is 1 greater than the input. When the binary input is 4, 5, 6, or 7, the binary output is one less than the input.
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- Design a combinational circuit with three inputs x, y, and z and three outputs A, B, and C. When the binary input is 0, 1, 2, or 3, the binary output is one greater than the input. When the binary input is 4, 5, 6, or 7, the binary output is two less than the input.Design a combinational circuit with three inputs x, y, and z, and three outputs, A, B, and C. When the binary input is 0, 1, 2, or 3, the binary output is one greater than the input. For example, if the inputs are 000, the outputs are 001. When the binary input is 4, 5, 6, or 7, the binary output is two less than the input. For example, when inputs are100, the outputs are 010. Show the truth table for the inputs and outputs. please show all steps , dont just explainDesign a combinational circuit with three inputs and one output.(a) The output is 1 when the binary value of the inputs is less than B. The output is 0 otherwise.
- Design a combinational circuit with three inputs and one output. The output is 1 when the binary value of the inputs is less than 3. The output is 0 otherwise.Design the simplest circuit that has three inputs, a, b, and c, which returns an output value of 1 whenever g and b are complements of each other or b and c are complements of each other, otherwise the output is 0. Realize the circuit using 4input , 3output PALDesign a combinational circuit with three inputs and one output.1. (a) The output is 1 when the binary value of the inputs is less than 3. The output is 0 otherwise.2. (b) The output is 1 when the binary value of the inputs is an even number.
- Implement a combinational circuit with three inputs x, y, and z and three outputs A, B, and C.When the binary input is equal to 0, 1, 2 or 3, then the output is equal to the input + 1.When the binary input is 4, 5, 6 or 7 then the binary output is equal to the input – 2.Design a combinational logic circuit that takes a 3–bit input and has one output P. The P output should be active high only when the inputs corresponds to a prime number Note: the prime numbers: Prime numbers are 2, 3, 5, 7… Select one: a. P= AC+B b. P= A'C+A'B c. P= AC+A'B d. P= AC+A'B'Write the three outputs of X, Y and Z in terms of the four inputs A, B, C and D for the follow logic gates configuration ---This is my answer: I am unsure if it is right. X = A + (A’B’ * (B’+C’) = A + (A’+B’)*(B’*C’) Y = ((A’+B’)*(B’*C’))*((B’*C’)+CD)Z = (B+C)*(C’+D’)*D’
- Design a combinational circuit with three inputs A, B, & C. The output Z is HIGH when the binary value of the inputs is an EVEN number and is greater than TWO. Draw the circuit using ONLY NOR gates.Design a combinational circuit with four input lines that represent a decimal digit in BCD and four output lines that generate the 9's complement of the input digit. Provide a fifth output that detects an error in the input BCD number. This output should be equal to logic 1 when the four inputs have one of the unused combinations of the BCD code in tinkercad. Just provide even a photo of it. Thank you so much!Given a 4-bit signed integer, design a circuit that outputs its absolute value. You can assume that the input will always have a valid output. (a) Draw a logic diagram of this circuit. You may use 4-bit half adder(s), 2x1 4-bit multiplexer(s), and any logic gate(s) in your design. (b) With the following Verilog code, implement your design above in Verilog. module half_adder (input [3:0] a, input [3:0] b, output [3:0] s); assign s = a + b; endmodule module mux(input [3:0] D0, input [3:0] D1, input S, output reg [3:0] O); always @(*) begin if (S == 0) O = D0; else if (S == 1) O = D1; else O = 4’bx; end endmodule