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Asked May 18, 2019

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Determine if y=e−x+8x−9 is a solution to the initial value problem given by y′+1=8x−y and y(0)=−8.

Step 1

The given differential equation is y′+1=8x−y.

The solution of the deferential equation is given as, y=e^{-x} +8x−9

Differentiate y=e^{-x} +8x−9 with respect to x.

Step 2

Substitute y’=- e^{-x} +8 and y=e^{-x} +8x−9 in y′+1=8x−y.

Step 3

solve LHS...

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